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2. Consider a large population with mean μ and known standard deviation σ = 5. There are two independent simple random sample
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The margin of error for both the samples are respectivley 0.8 and 0.49. The lowest among the two is 0.49. The difference between \bar{X_1} and \bar{X_2} ieX1 X2 must be less than 0.49 for \bar{X_1}\epsilon CI_2 and \bar{X_2}\epsilon CI_1 at the same time. ie to find the required probability all we need to find is P(|X1-Xy < 0.49) = Pl(리 < 0.49/V50) = 0.055

{since X1 X2 has normal distribution with mean zero and variance =52 +52- 50}

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