Suppose the population standard deviation is known. Suppose we take three independent samples and report a...
Suppose the population standard deviation is known. Suppose we take three independent samples and report a 95% confidence interval for the population mean μ for each set of data. What is the probability that a majority of the three confidence intervals contain the true population mean μ (rounded to four decimal places)? (Remember to express your answer as a proportion.)
Homework Answers
| here this is binomial with parameter n=3 and p=0.95 |
probability that a majority of the three confidence intervals contain the true population mean μ
=P(X=2)+P(X=3)=(3C2)*(0.95)2*(0.05)1+(3C3)*(0.95)3*(0.05)0 =3971/4000 =0.9928
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