Question

1A rigid container is divided into two compartments of equal volume by a partition 0nc compartment contains 1 mole of ideal g

B) i) Partition Removed NAINB NA +N 0 X +X x, +X, x, + X, All Ideal Gas n Kemov ASTo0 ASror = 2R In 2 + 3R In (2/3)-Rin (32/2

I thought when A has 2 mol and B has 1mol
mole fraction would be 2/3 for A and 1/3 for B

then the result is

delta S = -R (3N)*((2/3)ln(2/3) + (1/3)ln(1/3))
(and this was actually the answer of (4)!)

but the result is 3Rln(2).

Where am i wrong?

what is the difference between microstates in

2mol A 1mol B

and

2mol A 1mol A ?

1A rigid container is divided into two compartments of equal volume by a partition 0nc compartment contains 1 mole of ideal gas A at 1 atm, and the other contains 1 mole of ideal gas B at 1 atm. Calculate the increase in entropy which occurs when the partition between the two compartments is removed. If the first compartment had contained 2 moles of ideal gas A, what would have bee corresponding increases in entropy in each of the above two situations if both compartments had contained ideal gas A. n the increase in entropy when the partition was removed? C
B) i) Partition Removed NAINB NA +N 0 X +X x, +X, x, + X, All Ideal Gas n Kemov ASTo0 ASror = 2R In 2 + 3R In (2/3)-Rin (32/27)
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Answer #1

001 the tor and condition :) 0 hho 3 -RS1386-2.1970 099

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