Given the height function is s(T)--1672+555 Find the velocity v (T) dT (-1672+555) dT -16(2T)+0 -327 When the dollar hits the ground s(T) 0 Solve s(T) 0 -167 +555-0T 555 T +1555 The time should be positive so, T--V555 Findv(T) when TV555 v-V555-32-V555 16 4 4 4 =-8 /555 ~-1 88.46ft/sec