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Remarks: In all algorithm, always prove why they work. ALWAYS, analyze the com- plexity of your algorithms. In all algorithms

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Answer #1

1. This can be solved in O(m + n) running time,

  • We know that incrementing the capacity of e by 1 will result in increasing the max flow at most 1.
  • Starting with the current max flow f, you only need to find an augmenting path in the residual graph one more time, which costs O(m+n) time.
  • As each augmentation increments the flow value by at least 1,  it is guaranteed after the augmentation the flow achieved is maximum.

2. The solution which I proposed for Q1 will help only for incrementing and for +5 I think yes there is a possibility that the max flow won't change.

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