Question

the amounts in first section are correct. can someone help with the rest and make sure what I have is correct?

CALCULATIONS 1) From your data,caculate the mass of Na,CO, usod Rocond your result in the Calculton Reselts table below 2) Feom your data, calcelate the mass of NaCl produced Recoed your nevelt in the Cakulation Result. table below-y2.OSS 큐 o.01 g / Cakslatison Reuhs sble 3) From your data, caleulate the mols of Na,C0, and mols of NaC1 Show all calculation work below, Recoed your resuts in the Calculation Resalts table Mass of Na CO Mass of NaC Mols of Mels of D-002 mol ) Caleulate the sisplest wbole number mole ratio of Na,0O,: NaCL Show all caleulation work below 2) How does your experimental ratio compare to the accepted 1:2 ratio? If they are different, explain what might have caused the difference accepted wire-experimental value accepted val 3) Calculate the percent error. %E x 100%

Answer 1

1. Mass of Na₂CO₃ = (Mass of container + Na₂CO₃) - Mass of Na₂CO₃ = 42.057 - 42.055 = 0.002 g

2. Mass of NaCl = (Mass of container + Mass of NaCl after second heating ) - Mass of container = 42.070 - 42.055 = 0.015 g

3. Molar mass of Na₂CO₃ = (2* mass of Na ) + Mass of C + (3* mass of O) = (2*23) + 12 + (3*16) = 106 g/mol

Molar mass of NaCl = Mass of Na + Mass of Cl = 23 + 35.44 = 58.44 g/mol

Moles of Na₂CO₃ = Mass/ molar mass = 0.002 g / (106 g/mol) = 0.0000189 mol = 1.89 *10^-5 mol

moles of NaCl = 0.015 g/ (58.44 g/mol) = 0.000257 mol = 2.57 *10^-4 mol

Calculated results

1. Ratio of moles of Na₂CO₃ and NaCl is:

1.89 *10^-5 mol Na₂CO₃ : 2.57 *10^-4 mol NaCl

1.89 *10^-5 mol Na₂CO₃ /1.89 *10^-5 mol : 2.57 *10^-4 mol NaCl /1.89 *10^-5 mol

1 : 13.6

4: 68

2. It is different

Reasons : Heating is not complete.

(b) Balance is not calibrated before use

3) Ratio we have is 4/68 = 0.059

and actual is 1/2 = 0.5

%E = ((0.5- 0.059) /0.5)*100% = 88.2%