Pls answer the follow:
Strength and Stiffness of Second-Growth Douglas-Fir Dimension Lumber" : 35-43) except that the sample sizes there were larger] Forest Products J, 1991 Grade J 10 10 10 1.63 27 1.56 ·24 1.42 .26
1. Problem 10.5 page 419 a. What is x..? b. What is SSTr? c. Compute s2 for each group d. Compute SSE. e. Compute SST. Put SSTr, SSE, and SS Total into ANOVA table f. What are DF for ANOVA table? g. Compute MSTr and MSE. h. Compute the F statistic i. State hypotheses for the F test. j. What are DF for the F test? What is the.05 upper tail F critical value? k. State a conclusion about the test.
Homework Answers
Add Answer to:
Consider the following summary data on the modulus of elasticity (X 10 psi) for lumber of three d...
Consider the following summary data on the modulus of elasticity (✕ 106 psi) for lumber of...
Consider the following summary data on the modulus of elasticity
(✕ 106 psi) for lumber of three different grades.
Grade
J
xi.
si
1
11
1.61
0.22
2
11
1.55
0.23
3
11
1.42
0.21
Use this data and a significance level of 0.01 to test the null
hypothesis of no difference in mean modulus of elasticity for the
three grades. Calculate the test statistic. (Round your answer to
two decimal places.)
f =
What can be said about the...
Consider the following summary data on the modulus of elasticity ( 106 psi) for lumber of...
Consider the following summary data on the modulus of elasticity ( 106 psi) for lumber of three different grades. Grade J Xi. Si 1 11 1.62 0.23 11 1.61 0.22 11 1.54 0.25 Use this data and a significance level of 0.01 to test the null hypothesis of no difference in mean modulus of elasticity for the three grades. Calculate the test statistic. (Round your answer to two decimal places.) f= What can be said about the p-value for the...
1 Consider the following summary data on the modulus of elasticity ( 105 psi) for lumber...
1 Consider the following summary data on the modulus of elasticity ( 105 psi) for lumber of three different grades. Grades 1.64 0.21 2 1.54 0.23 3 71.42 0.22 Use this data and a significance level of 0.01 to test the null hypothesis of no difference in mean modulus of elasticity for the three grades. Calculate the test statistic. (Round your answer to two decimal places.) What can be said about the P-value for the test? OP-value > 0.100 0.050...
The data shown to the right are from independent simple random samples from three populations. Use...
The data shown to the right are from independent simple random samples from three populations. Use these data to complete parts (a) through (d). Sample 1 Sample 2 Sample 3 Click the icon to view a table of values of Fa Calculate SST, SSTR, and SSE using the computing formulas. SST = SSTR= SSE (Type an integer or a decimal. Do not round.) (Type an integer or a decimal. Do not round.) (Type an integer or a decimal. Do not...
The following are three observations collected from treatment 1, five observations collected from treatment 2, and...
The following are three observations collected from treatment 1, five observations collected from treatment 2, and four observations collected from treatment 3. Test the hypothesis that are equal at the 0.05 significance level. Treatment 1__ Treatment 2__ Treatment 3 8 __________ 3________ 3 11__________ 2________ 4 10__________ 1________ 5 0___________3_________ 4 0___________ 2________ 0 a-1. State the null hypothesis and the alternate hypothesis. b. What is the decision rule? c. Compute SST, SSE, and SS total. d. Complete an ANOVA...
The following are six observations collected from treatment 1, ten observations collected from treatment, and eight obs...
The following are six observations collected from treatment 1,
ten observations collected from treatment, and eight observations
collected from treatment 3. Test the hypothesis that the treatment
means are equal at the 0.05 significance level
??⭐️
The following are six observations collected from treatment 1, ten observations collected from treatment 2, and eight observations collected from treatment 3. Test the hypothesis that the treatment means are equal at the 0.05 significance level Treatment 1 Treatment 2 Treatment 3 6 2...
0 2 10 0 2 8 Consider the multiple regression model where є¡ ~ iid Ņ(0, σ*) for i = i, 2, 3, 4, 5...
0 2 10 0 2 8 Consider the multiple regression model where є¡ ~ iid Ņ(0, σ*) for i = i, 2, 3, 4, 5. (c) Fill in the values for the following ANOVA table: Source of Variation Sum of Squares df Mean Square F Regression on Xi, X2 Error Total (Corrected) (d) State the nul and alternative hypotheses associated with the F test from the ANOVA table in part (c) and do the F test (e) Compute R2 (f)...
The following data show the brand, price (S), and the overall score for 6 stereo headphones...
The following data show the brand, price (S), and the overall score for 6 stereo headphones that were tested by Consumer Reports. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from O (lowest) to 10° (highest). The estimated regression euation for these data is ,-2S857·0291x,-here x-price (s) and y " overall score. Price Score 76 71 61 160 85 70 60 45 Koss 30 35 VC Round your answers to three decimal...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
Consider the following summary data on the modulus of elasticity
(✕ 106 psi) for lumber of three different grades.
Grade
J
xi.
si
1
11
1.61
0.22
2
11
1.55
0.23
3
11
1.42
0.21
Use this data and a significance level of 0.01 to test the null
hypothesis of no difference in mean modulus of elasticity for the
three grades. Calculate the test statistic. (Round your answer to
two decimal places.)
f =
What can be said about the...
Consider the following summary data on the modulus of elasticity ( 106 psi) for lumber of three different grades. Grade J Xi. Si 1 11 1.62 0.23 11 1.61 0.22 11 1.54 0.25 Use this data and a significance level of 0.01 to test the null hypothesis of no difference in mean modulus of elasticity for the three grades. Calculate the test statistic. (Round your answer to two decimal places.) f= What can be said about the p-value for the...
1 Consider the following summary data on the modulus of elasticity ( 105 psi) for lumber of three different grades. Grades 1.64 0.21 2 1.54 0.23 3 71.42 0.22 Use this data and a significance level of 0.01 to test the null hypothesis of no difference in mean modulus of elasticity for the three grades. Calculate the test statistic. (Round your answer to two decimal places.) What can be said about the P-value for the test? OP-value > 0.100 0.050...
The data shown to the right are from independent simple random samples from three populations. Use these data to complete parts (a) through (d). Sample 1 Sample 2 Sample 3 Click the icon to view a table of values of Fa Calculate SST, SSTR, and SSE using the computing formulas. SST = SSTR= SSE (Type an integer or a decimal. Do not round.) (Type an integer or a decimal. Do not round.) (Type an integer or a decimal. Do not...
The following are six observations collected from treatment 1,
ten observations collected from treatment, and eight observations
collected from treatment 3. Test the hypothesis that the treatment
means are equal at the 0.05 significance level
??⭐️
The following are six observations collected from treatment 1, ten observations collected from treatment 2, and eight observations collected from treatment 3. Test the hypothesis that the treatment means are equal at the 0.05 significance level Treatment 1 Treatment 2 Treatment 3 6 2...
0 2 10 0 2 8 Consider the multiple regression model where є¡ ~ iid Ņ(0, σ*) for i = i, 2, 3, 4, 5. (c) Fill in the values for the following ANOVA table: Source of Variation Sum of Squares df Mean Square F Regression on Xi, X2 Error Total (Corrected) (d) State the nul and alternative hypotheses associated with the F test from the ANOVA table in part (c) and do the F test (e) Compute R2 (f)...
The following data show the brand, price (S), and the overall score for 6 stereo headphones that were tested by Consumer Reports. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from O (lowest) to 10° (highest). The estimated regression euation for these data is ,-2S857·0291x,-here x-price (s) and y " overall score. Price Score 76 71 61 160 85 70 60 45 Koss 30 35 VC Round your answers to three decimal...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
Most questions answered within 3 hours.
-
A square current loop 5.4 cm on each side carries a 510 mA
current. The loop...
asked 18 minutes ago -
What are five tips in conducting knowledge assessment/literature
review research? Each of these tips needs to...
asked 54 minutes ago -
Antigen presenting cells link innate and adaptive immune
responses. In the theoretical scenario where phagosomes cannot...
asked 1 hour ago -
Dealing with conflict, in my opinion, is a skill and an art. I
believe that those...
asked 1 hour ago -
6. A long straight wire with circular cross section and radius
1.5 cm carries a 1.2...
asked 1 hour ago -
Deacon Corporation has provided the following financial data
from its balance sheet and income statement:
Year...
asked 2 hours ago -
List and discuss at least three variables from everyday life for
which you expect the variable ...
asked 2 hours ago -
A high-pass filter consists of a 1.60 μF capacitor in series
with a 125 Ω resistor....
asked 2 hours ago -
A newly developed artificial intelligence has trouble
distinguishing hand-written numbers from hand-written alphabets.
There are pictures...
asked 2 hours ago -
The carbonate ion CO3 2- has multiple resonance structures.
a. Draw them and assign the hybridization...
asked 2 hours ago -
In doing an allocation for a basket purchase
Use the individual costs and the total market...
asked 2 hours ago -
what were the social political and economic causes and impacts of
the late 19th century urban...
asked 2 hours ago