Question
The following are six observations collected from treatment 1, ten observations collected from treatment, and eight observations collected from treatment 3. Test the hypothesis that the treatment means are equal at the 0.05 significance level

??⭐️

The following are six observations collected from treatment 1, ten observations collected from treatment 2, and eight observa
a. State the null hypothesis and the alternate hypothesis. HO H1 p3 all the same H1: Treatmer 12 vII
a. State the null hypothesis and the alternate hypothesis. HO:1 u3 H1: Treatment means same v A
a. State the null hypothesis and the alternate hypothesis. H0 μ1 2 p3. H1: Treatment means all the same are are not
b. What is the decision rule? (Round your answer to 2 decimal places.) Reject HO if F c. Compute SST, SSE, and SS total. (Rou
d. Complete an ANOVA table. (Round SS, MS, and Fvalues to 2 decimal places.) Source SS df MS Treatments Error Total e. State
0 0
Add a comment Improve this question Transcribed image text
Answer #1


Answer Date: 11/11/2019 To test the hypothesis is that the treatment means are not all the same at 5% level of significance.From the F distribution at 5% level of significance table, show degree of freedom treatment is, df= k-1 = 3-1 = 2 and degreeThe SS Treatment, SS Error and SS total is, 1) By using Excel software, find SS Treatment, SS Error and SS total with the helAn ANOVA table is, By using Excel software, find ANOVA table with the help of following steps: 1) Import the data. Choose ANOThe F-test statistics is 9.30 is greater than F-critical value which is 3.47, the null hypothesis is rejected at 5% level of

Add a comment
Know the answer?
Add Answer to:
The following are six observations collected from treatment 1, ten observations collected from treatment, and eight obs...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The following are six observations collected from treatment 1, four observations collected from treatment 2, and...

    The following are six observations collected from treatment 1, four observations collected from treatment 2, and five observations collected from treatment 3. Test the hypothesis at the 0.05 significance level that the treatment means are equal. Treatment 1 ___ Treatment 2 ___ Treatment 3 9_____________ 13 __________ 10 7_____________ 20___________ 9 11___________    14___________ 15 9 ____________ 13 ____________14 12____________ 0 ___________ 15 10_____________0_____________0 a. State the null and the alternate hypothesis. b. What is the decision rule c. Compute...

  • The following are three observations collected from treatment 1, five observations collected from treatment 2, and...

    The following are three observations collected from treatment 1, five observations collected from treatment 2, and four observations collected from treatment 3. Test the hypothesis that are equal at the 0.05 significance level. Treatment 1__ Treatment 2__ Treatment 3 8 __________ 3________ 3 11__________ 2________ 4 10__________ 1________ 5 0___________3_________ 4 0___________ 2________ 0 a-1. State the null hypothesis and the alternate hypothesis. b. What is the decision rule? c. Compute SST, SSE, and SS total. d. Complete an ANOVA...

  • Given the following sample information, test the hypothesis that the treatment means are equal at the

    Given the following sample information, test the hypothesis that the treatment means are equal at the .05 significance level. Treatment 1 Treatment 2 Treatment 3 3 9 6 2 6 3 5 5 5 1 6 5 3 8 5 1 5 4 4 1 7 5 6 4 1. State the null hypothesis and the alternate hypothesis. 2. What is the decision rule? 3. Compute SST, SSE, and SS total. 4. Complete an ANOVA table. 5. State your decision...

  • The management of discount furniture a chain of discount furniture stores in the north east , des...

    The management of discount furniture a chain of discount furniture stores in the north east , designed an incentive plan for sales person. To evaluate this innocative plan , 12 salespeople were selected at random and their weekly incomes before and after the plan were recorded. 425 (456 / 903 ) ト Θθ 140%,属密团甲 (+) : 140% 7. The following is sample information. Test the hypothesis that the treatment means are equal. Use the .05 significance level. Treatment 1 Treatment...

  • Treatment 1 Treatment 2 Treatment 3 0 1 6 1 4 5 0 1 6 3...

    Treatment 1 Treatment 2 Treatment 3 0 1 6 1 4 5 0 1 6 3 2 3 T = 4 T = 8 T = 20 SS = 6 SS = 6 SS = 6    N = 12     G = 32 ƩX2= 138 1a. Conduct a single-factor independent-measures ANOVA to test the hypothesis that there are significant differences in the mean scores among the three treatment conditions. Use α = .01. The alternative hypothesis is Group of answer choices...

  • The options for each of part c. are:   - At least one mean is different -...

    The options for each of part c. are:   - At least one mean is different - The means are the same. - The standard deviations are different. - The standard deviations are the same. Exercise 12-15 (LO12-4) The following data are given for a two-factor ANOVA with two treatments and three blocks. Treatment Block 1 2 A 40 36 B 33 27 C 46 39 Using the 0.05 significance level conduct a test of hypothesis to determine whether the block...

  • Topic: ANOVA Topic: ANOVA 1- An experiment was conducted using a randomized block design. The data...

    Topic: ANOVA Topic: ANOVA 1- An experiment was conducted using a randomized block design. The data from the experiment are displayed in the following table. Block Treatment 1 2 3 1 2 3 5 2 8 6 7 3 7 6 5 a) Fill in the missing entries in the ANOVA table. Source df SS MS F Treatment 2 21.5555 Block 2 Error 4 Total 8 30.2222 b) Specify the null use to investigate whether a difference exists among the...

  • The following hypotheses are given. HO: IT = 0.40 HAT+0.40 A sample of 120 observations revealed...

    The following hypotheses are given. HO: IT = 0.40 HAT+0.40 A sample of 120 observations revealed that p=0.30. At the 0.05 significance level, can the null hypothesis be rejected? a. State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answers to 2 decimal places.) Reject HO and accept H1 when z< or z> b. Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to...

  • The following data were collected from a repeated-measures study. Perform an ANOVA. Use a .05 alpha...

    The following data were collected from a repeated-measures study. Perform an ANOVA. Use a .05 alpha level. (10 POINTS) Treatment A B G = 36 EX? = 192 4 4 8 T= 12 T= 24 SS = 4 SS 8 1) State the null hypothesis. 2) Calculate necessary statistics (USE AN ANOVA even though K=2, and a=.05). 3) Make a decision about your null hypothesis and explain what that decision means. 4) Make a conclusion about your IV and DV...

  • 9.2.01 Treatment Placebo group and from norruse 0.055 A study was done using a treatment group...

    9.2.01 Treatment Placebo group and from norruse 0.055 A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. n x 25 2.31 0.66 2.61 0.92 O C. Ho: H1 H2 Hy:...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT