Question

The management of discount furniture a chain of discount furniture stores in the north east , designed an incentive plan for sales person. To evaluate this innocative plan , 12 salespeople were selected at random and their weekly incomes before and after the plan were recorded.

425 (456 / 903 ) ト Θθ 140%,属密团甲 (+) : 140% 7. The following is sample information. Test the hypothesis that the treatment means are equal. Use the .05 significance level. Treatment 1 Treatment Treatment 3 10 a. State the null hypothesis and the alternate hypotheses b. What is the decision rule? c. Compute SST, SSE and SS total. d. Complete an ANOVA table. e. State your decision regarding the null hypothesis. 8. The following is sample information. Test the hypothesis at the .05 significance level th the treatment means are equal. Treatment Treatment Treatment3 13 10

Answer 1

a) The null hypothesis is -

H₀ :$\mu_{1}=\mu_{2}=\mu_{3}$ against H₁: atlest one $\mu_{i}\neq \mu_{j}$ for all i=j=1,2,3

b) Decision rule -

If, calculates p-value for the test is less than $\alpha$ =0.05, then reject H₀ otherwise fail to reject 100* $\alpha$ % level of significant

c) the values of SST, SSE and SS total

SST = 62.17, SSE = 12.75, SS total = 74.92

d)

ANOVA Table    
Source        DF        SS        MS        F       P-value
Treatmen   2    62.17     31.08    21.94    0.000
Error      9        12.75      1.42
Total            11       74.92

e) Here, P-value is less than $\alpha$ =0.05 So we reject H₀ at 5 % level of significance.