The null and alternate hypotheses are: |
H0 : μ1 = μ2 |
H1 : μ1 ≠ μ2 |
A random sample of 11 observations from Population 1 revealed a sample mean of 21 and sample deviation of 3.5. A random sample of 7 observations from Population 2 revealed a sample mean of 23 and sample standard deviation of 3.8. The underlying population standard deviations are unknown but are assumed to be equal. |
At the .05 significance level, is there a difference between the population means? |
(a) |
State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answer to 3 decimal places.) |
The decision rule is to reject H0 if t < or t > . |
(b) | Compute the pooled estimate of the population variance. (Carry at least 3 decimal places in all intermediate calculations. Round your answer to 3 decimal places.) |
Pooled estimate of the population variance |
(c) |
Compute the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) |
Test statistic |
(d) | State your decision about the null hypothesis. |
(Click to select)Do not rejectReject H0 . |
a)
This is two tailed test, for α = 0.05 and df = n1 + n2 - 2 =
16
Critical value of t are -2.12 and 2.12.
Hence reject H0 if t < -2.120 or t > 2.120
b)
Pooled Variance
sp = sqrt((((n1 - 1)*s1^2 + (n2 - 1)*s2^2)/(n1 + n2 - 2))*(1/n1 +
1/n2))
sp = sqrt((((11 - 1)*3.5^2 + (7 - 1)*3.8^2)/(11 + 7 - 2))*(1/11 +
1/7))
sp = 1.748
c)
Test statistic,
t = (x1bar - x2bar)/sp
t = (21 - 23)/1.748
t = -1.144
d)
Do not Reject H0 .
The null and alternate hypotheses are: H0 : μ1 = μ2 H1 : μ1 ≠ μ2 A random sample of 8 observations from Population 1 revealed a sample mean of 25 and sample deviation of 4.5. A random sample of 8 observations from Population 2 revealed a sample mean of 26 and sample standard deviation of 3.5. The underlying population standard deviations are unknown but are assumed to be equal. At the .05 significance level, is there a difference between...
The null and alternate hypotheses are: H0: μ1 ≤ μ2 H1: μ1 > μ2 A random sample of 27 items from the first population showed a mean of 110 and a standard deviation of 15. A sample of 19 items for the second population showed a mean of 100 and a standard deviation of 6. Use the 0.025 significant level. a. Find the degrees of freedom for unequal variance test. (Round down your answer to the nearest whole number.) b....
The null and alternate hypotheses are: He: Th = 12 Hg: Th Th A sample of 200 observations from the first population indicated that X1 is 170. A sample of 150 observations from the second population revealed x2 to be 110. Use the 0.05 significance level to test the hypothesis. a. State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) The decision rule is to reject HO if z...
The following hypotheses are given. H0 : π ≤ 0.83 H1 : π > 0.83 A sample of 100 observations revealed that p = 0.87. At the 0.10 significance level, can the null hypothesis be rejected? State the decision rule. (Round your answer to 2 decimal places.) Compute the value of the test statistic. (Round your answer to 2 decimal places.) What is your decision regarding the null hypothesis? Do not reject H0. Reject H0. question 2: The number of...
pevious attempt. Exercise 15-8 (LO15-2) The null and alternate hypotheses are: A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the s population revealed x2 to be 110. Use the 0.05 significance level to test the hypothesis. econd a. State the decisio n rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) The decision rule istojecHzis inside1.96(196 b. Compute the pooled...
Given the following hypotheses: H0: μ ≤ 13 H1: μ > 13 A random sample of 10 observations is selected from a normal population. The sample mean was 11 and the sample standard deviation 3.6. Using the 0.05 significance level: State the decision rule. (Round your answer to 3 decimal places.) Compute the value of the test statistic. (Negative answers should be indicated by a minus sign. Round your answer to 3 decimal places.) What is your decision regarding the...
#3 Given the following hypotheses: H0: μ = 520 H1: μ ≠ 520 A random sample of 18 observations is selected from a normal population. The sample mean was 529 and the sample standard deviation was 5. Using the 0.01 significance level: State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.) Compute the value of the test statistic. (Round your answer to 3 decimal places.) What is your decision...
Given the following hypotheses: H0: μ = 600 H1: μ ≠ 600 A random sample of 16 observations is selected from a normal population. The sample mean was 609 and the sample standard deviation 6. Using the 0.10 significance level: State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.) Reject H0 when the test statistic is outside the interval ( , ). ? Compute the value of the test...
Given the following hypotheses: H0: μ = 540 H1: μ ≠ 540 A random sample of 10 observations is selected from a normal population. The sample mean was 550 and the sample standard deviation was 6. Using the 0.10 significance level: State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.) Compute the value of the test statistic. (Round your answer to 3 decimal places.)
The null and alternate hypotheses are: H0: ?1 ? ?2 H1: ?1 > ?2 A random sample of 24 items from the first population showed a mean of 113 and a standard deviation of 13. A sample of 18 items for the second population showed a mean of 103 and a standard deviation of 14. A) Use the 0.05 significant level. Find the degrees of freedom for unequal variance test. (Round down your answer to the nearest whole number.) B)...