Question

The null and alternate hypotheses are: H0: μ1 ≤ μ2 H1: μ1 > μ2 A random...

The null and alternate hypotheses are:

H0: μ1μ2

H1: μ1 > μ2

A random sample of 27 items from the first population showed a mean of 110 and a standard deviation of 15. A sample of 19 items for the second population showed a mean of 100 and a standard deviation of 6. Use the 0.025 significant level.

a. Find the degrees of freedom for unequal variance test. (Round down your answer to the nearest whole number.)

b. State the decision rule for 0.025 significance level. (Round your answer to 3 decimal places.)

c. Compute the value of the test statistic. (Round your answer to 3 decimal places.)

d. What is your decision regarding the null hypothesis? Use the 0.03 significance level.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

riven thot First Secon d ,-27 97I5 O Unequal Vavance test Degrees of freedom: min(nun)- min ( 2五11) -1 -19- 18 elec -ei tsh >10-lo o 2 - 10 8-3汁1,898 3.19 1 t= 31241 tusing oble 3%, level de Reject. Hood

Add a comment
Know the answer?
Add Answer to:
The null and alternate hypotheses are: H0: μ1 ≤ μ2 H1: μ1 > μ2 A random...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The null and alternate hypotheses are: H0 : μ1 = μ2 H1 : μ1 ≠ μ2...

    The null and alternate hypotheses are: H0 : μ1 = μ2 H1 : μ1 ≠ μ2 A random sample of 8 observations from Population 1 revealed a sample mean of 25 and sample deviation of 4.5. A random sample of 8 observations from Population 2 revealed a sample mean of 26 and sample standard deviation of 3.5. The underlying population standard deviations are unknown but are assumed to be equal. At the .05 significance level, is there a difference between...

  • The null and alternate hypotheses are:    H0 : μ1 = μ2 H1 : μ1 ≠...

    The null and alternate hypotheses are:    H0 : μ1 = μ2 H1 : μ1 ≠ μ2    A random sample of 11 observations from Population 1 revealed a sample mean of 21 and sample deviation of 3.5. A random sample of 7 observations from Population 2 revealed a sample mean of 23 and sample standard deviation of 3.8. The underlying population standard deviations are unknown but are assumed to be equal. At the .05 significance level, is there a...

  • The null and alternate hypotheses are: H0: ?1 ? ?2 H1: ?1 > ?2 A random...

    The null and alternate hypotheses are: H0: ?1 ? ?2 H1: ?1 > ?2 A random sample of 24 items from the first population showed a mean of 113 and a standard deviation of 13. A sample of 18 items for the second population showed a mean of 103 and a standard deviation of 14. A) Use the 0.05 significant level. Find the degrees of freedom for unequal variance test. (Round down your answer to the nearest whole number.) B)...

  • stuck on this Exercise 11-14 (LO11-2) The null and alternate hypotheses are: random sample of 27...

    stuck on this Exercise 11-14 (LO11-2) The null and alternate hypotheses are: random sample of 27 tems from the first population showed a mean of 110 and a standard deviation of 15. A sample of 19 items for the second population showed a mean of 100 and a standard deviation of 6. Use the 0.025 significant level a. Find the de grees of freedom for unequal variance test. (Round down your answer to the nearest whole number) of freedom 21...

  • The null and alternate hypotheses are: H0:µ1≤µ2. H0:µ1>µ2. A random sample of 29 items from the first population show...

    The null and alternate hypotheses are: H0:µ1≤µ2. H0:µ1>µ2. A random sample of 29 items from the first population showed a mean of 112 and a standard deviation of 9. A sample of 15 items for the second population showed a mean of 97 and a standard deviation of 12. Use the .01 significance level. a. Find the degrees of freedom for unequal variance test b. State the decision rule for .1 significance level c. Compute the value of the test...

  • You wish to test the following claim (H1) at a significance level of α=0.005.       Ho:μ1=μ2       H1:μ1>μ2...

    You wish to test the following claim (H1) at a significance level of α=0.005.       Ho:μ1=μ2       H1:μ1>μ2 You obtain a sample of size n1=117 with a mean of M1=62.8 and a standard deviation of SD1=10.2 from the first population. You obtain a sample of size n2=114 with a mean of M2=57.5 and a standard deviation of SD2=12.8mfrom the second population. What is the critical value for this test? (Report answer accurate to three decimal places.) critical value = What is the...

  • The following hypotheses are given. H0 : π ≤ 0.83 H1 : π > 0.83 A...

    The following hypotheses are given. H0 : π ≤ 0.83 H1 : π > 0.83 A sample of 100 observations revealed that p = 0.87. At the 0.10 significance level, can the null hypothesis be rejected? State the decision rule. (Round your answer to 2 decimal places.) Compute the value of the test statistic. (Round your answer to 2 decimal places.) What is your decision regarding the null hypothesis? Do not reject H0. Reject H0. question 2: The number of...

  • The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...

    The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 11 12 14 18 Afternoon shift 9 10 13 16 At the .005 significance level, can we conclude there are more defects produced on the afternoon shift? Hint: For the...

  • The null and alternate hypotheses are:    H0 : μd ≤ 0 H1 : μd >...

    The null and alternate hypotheses are:    H0 : μd ≤ 0 H1 : μd > 0    The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.    Day       1 2 3 4   Day shift 11     10     14    19      Afternoon shift 10     9     14    16    At the .01 significance level, can we conclude there are more...

  • The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...

    The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 12 15 19 Afternoon shift 8 11 12 20 At the 0.050 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT