Question

stuck on this

Exercise 11-14 (LO11-2) The null and alternate hypotheses are: random sample of 27 tems from the first population showed a mean of 110 and a standard deviation of 15. A sample of 19 items for the second population showed a mean of 100 and a standard deviation of 6. Use the 0.025 significant level a. Find the de grees of freedom for unequal variance test. (Round down your answer to the nearest whole number) of freedom 21 b. State the decision rule for 0.025 significance level. (Round your answer to 3 decimal places.) 10 Next >

Answer 1

Ans:

a)df=36

(using calculator)

b)critical t value(right tailed)=2.028

Reject H₀,if t>2.028

c)

Test statistic:

t=(110-100)/SQRT((15^2/27)+(6^2/19))

t=3.127

d)p-value=tdist(3.127,36,1)=0.0017

As,p-value<0.03,The null hypothesis is rejected.