Consider the combustion chamber boundary (C), using natural gas and air entering and an exhaust g...
The exhaust gas from a combustion chamber has the following ultimate analysis, percent by mass: 25% N2, 45% CO, 2% H2, and 28% CO2. A sample of the gas mixture is taken and stored in a solid tank with the volume of 0.001 m3 . Determine (a) the total mass of mixture in the tank at 20℃ and 0.1 MPa (b) mole fraction of mixture in the tank at 20℃ and 0.1 MPa (c) heat transfer required to heat the...
n-Pentane is burned with excess air in a continuous combustion chamber. Below is a skeleton flowchart. n (mol n-pentane) Combustion Chamber 100 mol Dry Product Gas (DPG) Xp (mol n-pentane / mol DPG) Xaq (mol O2/mol DPG) Xco, (mol CO2/mol DPG) XNC (mol N2 mol DPG) n (mol H2O) Excess Air n2 (mol O2) na (mol N) Air Composition Correct. 169.25 If n2 were 45.0 moles, what would be the value of n4? mol the tolerance is +/-2% Your answer...
1.f) Methane gas (CH4) enters a combustion chamber at a rate of 3 kg/sec at a temperature of 25 °C. A 200% theoretical air is supplied at a temperature of 400K. At the middle of methane combustion process (i.e., after 50% of methane gas is burnt), liquid propane (C3H8) at 25°C is injected at a rate that produces neither CO nor O2 in the flue gases. Assume steady state and adiabatic process at 1 atm, calculate the following i. The...
The heater in a house burns natural gas with x% excess air according to the reaction: CH4 2 02>CO2 2 H2O The flue gas leaves the burner at Tout. The air and the natural gas (CH4) enter the burner Prepare a spreasheet for this system using a basis of one mole of methane feed to deter at standard conditons of 25°C and 1 atm pressure. mine: a) The standard heat for the combustion for the reaction above, b) The required...
Question Completion Status: QUESTION 1 10 points A hydrocarbon gas is burned with air. The dry-basis (without H20) product gas composition is 1.5 mole% CO, 6 mole% CO2, 8.2 mole% O2, and 84.3 mole% N2. ne(mol C) (mol no (malain (100 mol dry gas 0.21 mol Oymol 0.015 mol COmol dry gas 0.79 mol Ny/mol 0.060 mol CO2 mol dry gas 0.082 mol Oz moi dry g 0.843 mol Nymol dry gas "wmol H20) 1. Using the method of atomic...
Week 4 Process 1: Consider the process below: Water in Combustor Steam Generator Gas In Gas Out Combustor exit Steam Out A methane (CH) and air mixture is burnt in the combustor then the heat is recovered to produce steam. The CHa/air mixture comes in at 25°C and contains 10 kg/h of CH4 and 500 kg/h of air (assume 79% Nitrogen (N2) and 21 % Oxygen (O2)). The final outlet gas leaves at 100 °C. The combustion reaction follows the...
3. A process stream of 100 mol/s of n-Hexane vapor at 70.0 °C and 1 atm is fed into a furnace along with a process stream of 50.0% excess dry air (20% O2, 80% N2) at 70 °C and 1 atm. In the furnace, all the hexane is consumed, and the production rate of 60 mol/s CO is obtained. The reaction schemes for complete and incomplete combustion of n- hexane are given as: (1) C6H14 (9) + 5.02(g) – 6CO2(g)...
The cutoff text in the table is CO2 with r(nm)=0.230 Molecular collisions consider the atmosphere as made up from 80% N2 and 20% O2 gases. At a pressure P, the N2 and O2 gases will have partial pressure of PN and Po respectively so that P PN + Po. If nN and no are the concentration of N2 and O2 molecules respectively then PN nNkT, and Po nokT, Consider a vacuum chamber in which the total pressure is 10-5 torm...
1. (18 points) Consider the balanced gas phase combustion of dinitrotoluene, DNT (C7 HG(NO2)2): 2C7H6(NO2)2(g) + 3 O2(g) ---> 14 CO(g) +4 NH3(g). The products are carbon monoxide (CO) and ammonia (NH3). A gaseous mixture of DNT and O2(g) at 80°C is placed into a previously empty rigid container. When the above reaction goes to completion at 80°C, 0.15 atm of O2(g) is still present. The partial pressure of the NH3(g) produced is 1.00 atm. Assume all gases behave ideally....
In a vastly simplified view of human metabolism, we can assume that the body is deriving energy primarily from the following two reactions that are happening at the same time: 1- C15H31COOH + 23O2 -> 16CO2 + 16 H2O 2- C6H12O6 + 6O2-> 6 CO2 + 6H2O The first reaction more or less corresponds to "burning fat" while the second one corresponds to "burning sugar." In a metabolic experiment, an individual running on a treadmill is fitted with a mask delivering air and analyzing exhaled gas. Fresh...