a) Place the value of λ in which the absorbance is maximum, this point occurs at an absorbance of 1.063.
b) The known values of concentration versus absorbance are plotted:
The equation of the line is determined, which was:
Y = 0.1817 X + 0.0006
Where X: Concentration and Y: Absorbance, clear:
X = (Y - 0.0006) / 0.1817
The concentration at absorbance of 0.456 is calculated:
X = (0.456 - 0.0006) / 0.1817 = 2.51 mg Fe / L
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