Please refer following image for solution
Procedure: locate O1 O2 6cm apart on horizontal axis
- take 700 from O1 and locate A at 3cm
- take 400 from O2 and locate C at 4cm
- draw an arc of 7cm from A and another arc of 6cm from C intersection of two arcs will give us ppipo B
- Complete the polygon and measure the angles
3= 450 and 4= 1200
Procedure for velocity polygon:
- calculate the velocities of link 3 and 5 consider the scale
- locate fixed point O1 O2
- draw vector Va perpendicular to link OA with scale
- draw vector Vc perpendicular to link OC with scale
- from a extend the line perpendicular to AB and from c extend the line perpendicular to CB intersection will give is point b
- measure the length of vectors and multiply with scale we will get linear velocities
- divide linear velocity with length of link we will get angular velocity
Q2. The link lengths ofgeared five bar linkage and the values of λ., 02 and co2 are given as: L, ...
Problem: In a fourbar linkage, the link lengths and the values of 02, 02 and a2 are defined in the following table. (lengths in cm, angles in degree, angular velocities in rad/s). 6, LNCS Link 1 Link 2 Link 3 Link 4 02 002 02 6 2 7 9 30 10 0 02 04 For this mechanism, the coupler and the output angles can be found: 03 = 88.84º and 04 = 117.29º. (For practice, you are encouraged to find...
Kinematics please answer asap with clear work 2. (50 points) The link lengths of a linkage, shown in Figure 2 (not to scale), are L- 5" (ground), and 2-1" (input), L3 3.5" (coupler), L-3" (output or follower), respectively. The location of the coupler point P is given as RPA-4", and δ,-20° When the input link is at 6-55°, we have a-31.251° and θ4-1 18.561° for the open configuration. (a) Find the corresponding transmission angle at this configuration and the corresponding...