PHEONIX(PH) | CLEVELAND(CL) | CHICAGO(CH) | ||||||||
RENO(R) | 10 | 16 | 19 | 120 | ||||||
DENVER(D) | 12 | 14 | 13 | 200 | ||||||
PITTSBURG(P) | 18 | 12 | 12 | 160 | ||||||
140 | 160 | 180 | ||||||||
PHR | PHD | PHP | CLR | CLD | CLP | CHR | CHD | CHP | Total | |
DECISION VARIABLE | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | |
COST | 10 | 16 | 19 | 12 | 14 | 13 | 18 | 12 | 12 | SUM OF ALL DECISION VARIABLES MULTIPLIED BY COST |
PH | 3 | 140 | CONSTRAINTS | 1 | ||||||
CL | 3 | 160 | CONSTRAINTS | |||||||
CH | 3 | 180 | CONSTRAINTS | |||||||
R | 3 | 120 | CONSTRAINTS | |||||||
D | 3 | 200 | CONSTRAINTS | |||||||
P | 3 | 160 | CONSTRAINTS |
By this way. you will get the answer
ANSWER IS
PH | CL | CH | ||
R | 120 | 0 | 0 | 120 |
D | 20 | 0 | 180 | 200 |
P | 0 | 160 | 0 | 160 |
140 | 160 | 180 |
Cost is 5760
PHR | PHD | PHP | CLR | CLD | CLP | CHR | CHD | CHP | ||
120 | 20 | 0 | 0 | 0 | 160 | 0 | 180 | 0 | ||
1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | ||
Part Requirements by Product |
Part Inventory Levels |
|||||||||
Part Name | PH | CL | CH | Used | Available | |||||
PH(just for multiplication i put 1 here) | 1 | 1 | 1 | 140 | 140 | |||||
CL | 1 | 1 | 1 | 160 | 160 | |||||
CH | 1 | 1 | 1 | 180 | 180 | |||||
R | 120 | 0 | 0 | 120 | 120 | |||||
D | 20 | 0 | 180 | 200 | 200 | |||||
P | 0 | 160 | 0 | 160 | 160 | |||||
Profit per Unit | 10 | 16 | 19 | 12 | 14 | 13 | 18 | 12 | 12 | 5760 |
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