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QUESTION 19 3 points S In the reaction Mg0(s) → Mg(s) + + 0.502(g) the enthalpy change AH*) is +602(AHP) kj mol. 1 and the en
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Answer #1

ΔG = ΔH - TΔS

ΔG = (602 - T * 0.109 ) KJ / mol

@ 1000 K

ΔG = 602 - 1000*0.109 = 493 KJ / mol non spontaneous reaction so not feasible at 1000 K.

@ 6000 K

ΔG = 602 - 6000*0.109 = - 52 KJ / mol ΔG is negative so reaction is spontaneous and thus feasible at 6000 K.

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QUESTION 19 3 points S In the reaction Mg0(s) → Mg(s) + + 0.502(g) the enthalpy change AH*) is +6...
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