The standard Free energy is calculated per mole of CaCO3 . When 2.34 moles of CaCO3 react, the free energy is given by: Free energy change = 2.34 * Standard Free Energy Change
= 2.34 * 130.4 = 305.1 KJ
The Free Energy change of a reaction is also the amount of useful work that can be done by the reaction. This is therefore equal to 305.1 KJ
Consider the reaction CaCO3(s)Cao(s) + CO2(g The standard free energy change for this reaction is...
Consider the reaction 2HBr(g) H2(g) Br2(1) The standard free energy change for this reaction is 107.0 kJ. The free energy change when 2.50 moles of HBr(g) react at standard condition is kJ. What is the maximum amount of useful work that the reaction of 2.50 moles of HBr(g) is capable of producing in the surroundings under standard conditions? If no work can be done, enter none. kJ
Consider the reaction 2HBr(g) H2(g) Br2(1) The standard free energy change for this...
Consider the reaction: CaCO3(s)CaO(s) + CO2(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.26 moles of CaCO3(s) react at standard conditions. S°system = J/K
CaO (s) + CO2 (g) CaCO3 (s) Given the following information, what is the standard gibbs free energy change (°) at 35°C? H°rxn = -179 kJ/mol CaO (s) = 38.1 S° CO2 (g) = 213.8 S° CaCO3(s) = 91.7 S°
Consider the following reaction: CaO (s) + CO2 (g) → CaCO3 (g) If 12.9 g of carbon dioxide, CO2, react, how many grams of calcium carbonate, CaCO3, are produced?
Consider the decomposition of CaCO3 at standard conditions: CaCO3(s) >> CO2(g) + CaO(s) DeltaH=177.8 KJ/mol, DeltaS=160.5 J/K mol, DeltaG=130.3 KJ/mol, K=1.506x10^-23, Nonspontaneous until temp 1107.8 K or higher. What is the new concentration of CO2 at nonstandard temperature (1107.8k)?
Consider the decomposition of CaCO3 at standard conditions: CaCO3(s) >> CO2(g) + CaO(s) DeltaH=177.8 KJ/mol, DeltaS=160.5 J/K mol, DeltaG=130.3 KJ/mol, K=1.506x10^-23, Nonspontaneous until temp 1107.8 K or higher. What is the new concentration of CO2 at nonstandard temperature (1107.8k)?
Consider the reaction: CaCO3(s)/C2O(s) + CO2(8) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.58 moles of CaCO3(s) react at standard conditions. AS system JK Submit Answer Retry Entire Group 8 more group attempts remaining
Calculate ΔH for the following reaction, CaO(s) + CO2(g) → CaCO3(s) given the thermochemical equations below. 2 Ca(s) + O2(g) → 2 CaO(s) ΔH = -1270.2 kJ C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ 2 Ca(s) + 2 C(s) + 3 O2(g) → 2 CaCO3(s) ΔH = -2413.8 kJ A compound contains C, H and O as the elements. A 20.0 g-sample is comprised of 1.34 g H and also 8.00 g of C. What...
17-free energy
Consider the reaction: 2CO2(g) + SH2(g) - C2H2(g) + 4H2O(g) Using standard thermodynamic data at 298K, calculate the free energy change when 2.18 moles of CO (8) react at standard conditions AG rum kJ Submit Answer Retry Entire Group 7 more group attempts remaining Consider the reaction: 2CO2(g) + 5H2(g)—*C2H2(g) + 4H2O(g) Using standard thermodynamic data at 298K, calculate the free energy change when 2.18 moles of CO2(g) react at standard conditions. kJ AGⓇ rxn Submit Answer Retry...
For the endothermic reaction CACO3(s) CaO(s) +CO2(8) Le Chatelier's principle predicts that will result in an increase in the number of moles of CO2. increasing the temperature decreasing the temperature increasing the pressure removing some of the CaCO3 (s) none of these