Question

3-Connect a 5kΩ potentiometer (502) and connects the signal generator as indicated in the diagram below. Please note that the top pin of the potentiometer is connected to the positive terminal of the signal generator, the bottom one is connected to the negative terminal and the middle is connected to C2. Set the amplitude and frequency of the signal generator to 1Vrms and 1kHz, respectively. Using your multimeter (Vac) measure the magnitude of the incoming signal (Vsignal- divide it over two . Connect your multimeter between the middle pin of the potentiometer (Vx) and ground and turn the knob until Vx Vsignal/2. Then disconnect the potentiometer and measure the resistance between the top pin and the pin at the middle. That resistance value is your output resistance. Rout = vout/lout-1/1.07mA=934.58 Need to draw the small signal representation C2 Q1 5k test 1V (rms) 1kHz BE Q2N3904 RB2 RE 4-Repeat the same process but at the input to calculate the input resistance using a 5kΩ resistor (502) Rin= vtest/itest-1/444uA-2252.25 Need to draw the small signal representation Q1 RTest C1 VBEQ2N3904 test 1V (rms) ( 1kHz RE C2

Answer 1

emall sigal modal fo arauilO Vtes 2 1 c Re 2 178