17) (4 pts) Calculate the theoretical potential of the following cell. As it is written is the ce...
Calculate the theoretical cell potential for each of the following cells. Is the cell, as written, galvanic or electrolytic? a. Pb | PbSO_4 (sat'd), SO_4^2- (0.200 M) || Sn^2+ (0.150 M), Sn^4+ (0.250 M)|Pt b. Pt |Fe^3+ (0.0100M), Fe^2+ (0.00100M) || Ag^+ (0.200M), CuI (sat'd) |Cu d. Pt | UO_2^2+ (0.0100 M), U^4+ (0.0100 M), H^+ (1.00 times 10^-6 M) || AgClO (sat'd), KCI (1.00 times 10^-4 M) |Ag
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2+ (0.15 M) Fe2+ (0.0039 M) Fe(s) E =-0.440 V E+Cu = 0.339 V Fe2+/Fe Is the electrochemical cell spontaneous or not spontaneous -0.779 Ecell = as written at 25 C? not spontaneous spontaneous о Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 'C Pt(s) Sn2 (0.0024 M), Sn4+ (0.12 M) |...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Cu(s) Cu2+(0.14 M) | Fe2+(0.0044 M) Fe(s) Ecu?+Icu = 0.339 V Efez lfe = -0.440 V Ecell = v Is the electrochemical cell spontaneous or not spontaneous as written at 25 °C? O not spontaneous O spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2+(0.0048 M), Snº+(0.11 M) || Fe3+(0.12...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2 (0.12 M |Fe2 (0.0012 M) Fe(s) E2 =-0.440 V Efe/Fe = 0.339 V Cu2t/Cu Is the electrochemical cell spontaneous or not spontaneous Ecell V as written at 25 °C? not spontaneous spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2(0.0060 M), Sn4+(0.14 M) Fe3+(0.13 M), Fe2+(0.0056 M) Pt(s)...
Con 14 of 16 > Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that (Sn²+] = 0.0590 M, [Fe3+1 = 0.0451 M, [Sn+1 = 0.00484 M, and [Fe2+] = 0.00958 M. Standard reduction potentials can be found in this table. Sn?+ (aq) + 2 Fe?+ (aq) = Sn**(aq) + 2 Fe²+(aq) V E =
Calculate the cell potential for the following reaction as written at 25.00 degree C, given that [Zn^2+] = 0.875 M and [Fe^2+] = 0.0160 M. Standard reduction potentials can be found here. Zn(s) + Fe^2+(aq) reversible Zn^2+ (aq) + Fe(s) E = V
Question 9 (1 point) Is the following galvanic cell going to proceed spontaneously as written? If yes, what will be the cell potential? | Mn (s) | Mn2+ (0.05 M) || Agt (2.5 M) | Ag (s) | Yes. The cell potential will be 2.05 V as written Yes. The cell potential will be 1.90 V as written Yes. The cell potential will be 2.11 V as written No, the galvanic cell will not be spontaneous as written Show Report...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 ∘ C . Cu ( s ) ∣ ∣ Cu 2 + ( 0.13 M ) ∥ ∥ Fe 2 + ( 0.0011 M ) ∣ ∣ Fe ( s ) E ∘ Cu 2 + / Cu = 0.339 V E ∘ Fe 2 + / Fe = − 0.440 V E cell = V
Calculate the cell potential for the reaction as written at 25.00 °C, given that [Cr2+]=0.891 M and [Fe2+]=0.0120 M. Use the standard reduction potentials in this table. Cr(s)+Fe2+(aq)↽−−⇀ Cr2+(aq)+Fe(s) E= V
Calculate the cell potential for the reaction as written at 25.00 °C, given that [Mg2 Use the standard reduction potentials in this table 0801 M and [Fe+] 0.0120 M. Mg(s) + Fe2+(aq) Mg2+(aq) + Fe(s)