Calculate the theoretical cell potential for each of the following cells. Is the cell, as written,...
17) (4 pts) Calculate the theoretical potential of the following cell. As it is written is the cell a Galvanic cell? SHOwALL OF yOUR WORK FOR FULL CREDIT P(S)IU (0.02 M), UO, (a) (0.05 M), H' (a) (0.1 MFe(a)(0.03 M). Fe a)00D UC)2. 2 (aq)→11.4 (aq) E"= +0.334 V Fea)Fe -+0.771 V 43 17) (4 pts) Calculate the theoretical potential of the following cell. As it is written is the cell a Galvanic cell? SHOwALL OF yOUR WORK FOR FULL...
The following electrochemical cell was set up in the lab Pt│Fe(NO3)2, Fe(NO3)3││Ag(NO3)│Ag What is Ecell°? If a more complete description of the cell is Pt│Fe(NO3)2(0.200 M), Fe(NO3)2(0.150 M)││Ag(NO3)(0.200 M) │Ag what is Ecell? c. What is the spontaneous cell reaction for the cell conditions given in b.?
Con 14 of 16 > Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that (Sn²+] = 0.0590 M, [Fe3+1 = 0.0451 M, [Sn+1 = 0.00484 M, and [Fe2+] = 0.00958 M. Standard reduction potentials can be found in this table. Sn?+ (aq) + 2 Fe?+ (aq) = Sn**(aq) + 2 Fe²+(aq) V E =
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2+ (0.15 M) Fe2+ (0.0039 M) Fe(s) E =-0.440 V E+Cu = 0.339 V Fe2+/Fe Is the electrochemical cell spontaneous or not spontaneous -0.779 Ecell = as written at 25 C? not spontaneous spontaneous о Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 'C Pt(s) Sn2 (0.0024 M), Sn4+ (0.12 M) |...
Example 13 Calculate the potential for the following cell using (a) concentrations and (b) activities: aSO42-0.4nm and aZn2+ 0.6 nm, m-2.10-3 Zn ZnSO(xM), PbSO(sat'd) Pb where x 5.00X 10 ,2.00 X 10 3, 1.00 X 10 ,5.00 X 102 Example 13 Calculate the potential for the following cell using (a) concentrations and (b) activities: aSO42-0.4nm and aZn2+ 0.6 nm, m-2.10-3 Zn ZnSO(xM), PbSO(sat'd) Pb where x 5.00X 10 ,2.00 X 10 3, 1.00 X 10 ,5.00 X 102
6. Calculate the actual cell potential for: Ni | Ni (0.0825 M) || Ag(S20,)2 (0.00963 M), NaS203 (0.112 M) | Ag. The overall reaction will occur in a galvanic cell or an electrolytic cell? Identify the cathode and the anode if the cell is shorted. (12 points)
4. Write a balanced equation from each cell notation, then calculate thee of the cell, is it spontaneous or nonspontaneous? A. Cr(s) Crot || Cui Cu(s) B. Al(s) Al* | Ce Ce Pt C. Cu (s) Cu? || Al Al (s) Useful information: F= 96485 J/V mol electrons, AG ----F-Ecell AG --RTINK: Ece 0.0592/n*logK; EcellEcett -0.0592/n*logQ Ce (aq) + Ag+ (aq) + e Fet (aq) + Cu" (aq) + Cu (aq) + 2e 2H(aq) + 2 Pb (aq) + 2e...
calculate ecell for the following electrochemical cell at 25 C. Pt(s)| H2 (g,1.00 atm) | H+ (aq, 1.00 M) || (Pb2+ (aq, 0.150 M) | Pb (s) Pb^2+(aq) + 2e- ---> Pb (s) Eo=-0.126 V 2H^+ (aq) + 2e- ---> H2 (g) Eo=0.00 V Thank you!
Calculate the electrostatic potential of the cell at below 25 ° C .Pt (p) | H 2 (g, 200 kPa) | HNO 3 (aq, 0.10 M) || AgNO3 (aq, 0.0100 M) | Ag (s) E ° for Ag + + e- ® Ag (s) is 0.80 V.
Calculate Ecell for the following electrochemical cell at 25 degreeC Pt(s) | H2(g, 1.00 atm) | H+ (aq, 1.00 M) || Pb2+(aq, 0.150 M) | Pb(s) given the following standard reduction potentials. Pb2+(aq) + 2 e– --> Pb(s) Edegree = –0.126 V 2 H+ (aq) + 2 e– --> H2(g) Edegree = 0.000 V (Please show the steps)