c. What is the spontaneous cell reaction for the cell conditions given in b.?
The following electrochemical cell was set up in the lab Pt│Fe(NO3)2, Fe(NO3)3││Ag(NO3)│Ag What is Ecell°? If...
The following electrochemical cell was set up in the lab Ag(s)│Ag(NO3)(aq)││KMnO4(aq), HCl(aq), Mn(Cl)2(aq)│Pt(s) What is Ecell° for this galvanic cell? If a more complete description of the cell is Ag(s)│Ag(NO3)(aq, 0.50 M)││KMnO4(aq, 0.50 M), HCl(aq, 2.5 M), Mn(Cl)2(aq, 0.01 M)│Pt(s), Ag(s) what is Ecell? What is the balanced, spontaneous cell reaction for the cell conditions given in b.?
QUESTION 27 Calculate Ecell under non-standard conditions for the following electrochemical cell: Pt(s)| FeCl2 (aq, 0.150 M), FeCl3 (aq, 0.050 M) || Cl2 (9, 1 atm), NaCl (aq, 0.075 M) | Pt (s) -1.60 V 0.72 v 0.69 V -1.79 V 0.62 V none of these
Consider the following electrochemical cell at 298.15 K: Cd(s) | Cd(NO3)2 (aq, m = 0.200) || KCl (aq, m = 0.0150) | Ag(s) | AgCl(s) A) Write the overall reaction. B) Calculate the standard cell potential and ∆GR°. C) Calculate the cell potential and ∆GR assuming activity coefficients are 1.00. D) Calculate the cell potential and ∆GR using the Debye-Huckel limiting law for the mean ionic activity coefficients. E) Is the cell reaction spontaneous as written? F) How much electrochemical...
the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) fone 2 pts) a. Use the standard half-cell potentials listed below to calculate the standard cell potential (Eºcell) for 3 Sn(s) + 2 Fe* (aq) - 3 Sn2+ (aq) + 2 Fe(s) Sn 2(aq) + 2 e -Sn (s) E = -0.14 V Fe3+ (aq) + 3 e Fe(s) E° = -0.036 V A) -0.176 V B)-0.104 V C) +0.104 V D) +0.176 V b. Write...
Calculate Ecell for the following electrochemical cell at 25 degreeC Pt(s) | H2(g, 1.00 atm) | H+ (aq, 1.00 M) || Pb2+(aq, 0.150 M) | Pb(s) given the following standard reduction potentials. Pb2+(aq) + 2 e– --> Pb(s) Edegree = –0.126 V 2 H+ (aq) + 2 e– --> H2(g) Edegree = 0.000 V (Please show the steps)
calculate ecell for the following electrochemical cell at 25 C. Pt(s)| H2 (g,1.00 atm) | H+ (aq, 1.00 M) || (Pb2+ (aq, 0.150 M) | Pb (s) Pb^2+(aq) + 2e- ---> Pb (s) Eo=-0.126 V 2H^+ (aq) + 2e- ---> H2 (g) Eo=0.00 V Thank you!
What is [Fe+2] in the following electrochemical cell? SCE // Fe 2+ (xM) / Fe (s) Ecell = -0.725 V Esce = 0.242 V Answer: 0.035M Show work please
Answers and detailed explanations For the following electrochemical cell, calculate the potential and determine if the cell reaction is spontaneous as written at 25 °C. Cu(s)|Cu2+(0.15 M)||Fe2+(0.0020 M)|Fe(s) Ecuaticu = 0.339 V Efez-ffe = -0.440 V Ecell = Determine if the cell reaction is spontaneous as written. O spontaneous O not spontaneous
What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Ag concentration is 2.68x10-4 M and the Art concentration is 1.06 M ? 3Ag" (aq) + Al(s) +3Ag(s) + Ap+(aq) Answer: V The cell reaction as written above is spontaneous for the concentrations given: Submit Answer Retry Entire Group 4 more group attempts remaining What is the calculated value of the cell potential at 298K for an electrochemical cell...
Find Ecell for an electrochemical cell based on the following reaction with [MnO4−]=1.50M, [H+]=1.50M, and [Ag+]=0.0140M. E∘cell for the reaction is +0.88V. MnO4−(aq)+4H+(aq)+3Ag(s)→MnO2(s)+2H2O(l)+3Ag+(aq) Find for an electrochemical cell based on the following reaction with , , and . for the reaction is . 0.75 V 1.01 V 0.84 V 0.92 V