Which of the following are acceptable wavefunctions for a particle in a one-dimensional box? Check all that apply.
ψ(x) = C(1 - sin(nπx/a))
ψ(x) = Acos(nπx/a) + Bsin(nπx/a)
ψ(x) = E/cos(nπx/a)ψ(x) = D(a - x)xψ(x) = Cx3(x-a)
Which of the following are acceptable wavefunctions for a particle in a one-dimensional box? Chec...
Which of the following are acceptable wavefunctions for a particle in a one-dimensional box? Check all that apply. ψ(x) = C(1 - sin(nπx/a)) ψ(x) = Acos(nπx/a) + Bsin(nπx/a) ψ(x) = E/cos(nπx/a)ψ(x) = D(a - x)xψ(x) = Cx3(x-a)
For a one-dimensional particle in a box, the energies of the wavefunctions are directly proportional O a. n? b. the charge of the particle c. the mass of the particle ed the length
The following is an acceptable wavefunctions for a particle in a 2D rectangular box with infinite walls: (12 points) 12/ innxx -intnxx\ / innyy -innyy le Lx - e Lx 1 Ly – e Ly Lx 12Ly 16x9 = (+)* (24)*(7*-77)( ) a. Show that this wavefunction is normalized. (hint: you should expand the exponentials into their trigonemtric forms using Euler's formula) b. Show that the expectation value of px is equal to zero. (hint: use the trigonemtric forms again)
In solving the particle in a one dimensional infinite depth box problem (0k x < a) we started with the function following is a true statement? (a) The value of k is found by requiring that the solution be normalized. (b) The function wx) is not an eigenfunciton of the operator d2/dx2 (c) It is necessary that this function equals a when x=0 (ie, Ψ(0) = a). (d) The boundary condition at x = 0 is used to show that...
Instead of assuming that a one-dimensional particle has no energy (v(x)=0), consider the case of a one-dimensional particle which has finite, but constant, energy V(x)= V sub zero.. Show that the ID particle in a box wave functions. n(x)= A sin ((pi n x)/a). Also solve the Schrödinger equation for this potential, and determine the energies En Problem 2: Particle in a Box with Non-Zero Energy (2 points) Instead of assuming that a one-dimensional particle has no energy (V(x) =...
for a one-dimensional particle in a box, of the potential at x=+c is infinity, then the wave function at x=+c must be For a one-dimensional particle in a box, if the potential at x = +c is infinity, then the wavefunction at x = +c must be a. O b. a positive number less than 1 O c. a positive number greater than 1 d. 1
for a one-dimensional particle in a box, of the potential at x=+c is infinity, then the wave function at x=+c must be For a one-dimensional particle in a box, if the potential at x = +c is infinity, then the wavefunction at x = +c must be a. O b. a positive number less than 1 O c. a positive number greater than 1 d. 1
/a). The wavefunction for a particle in a one-dimensional box of length a is v = (2)"sin(n What is the probability of finding the particle in the middle third of the box for n = 2?
nh 61. The energy for one-dimensional particle-in-a-box is E=" 1. For a particle in a 0 three-dimensional cubic box (Lx=Ly=L2), if an energy level has twice the energy of the ground state, what is the degeneracy of this energy level? (B) 1 (C)2 (D) 3 (E) 4 (A) 0
When we discussed the particle in a box model, we defined our box to be from x=0 to x=a. Re- examine this problem, defining the box to be from -a to +a. Recall that the general solution for a particle in a region of V=0 is ψ = A sin kx + B cos kx. Apply the appropriate boundary conditions, figure out what k is (in terms of a), and normalize your solution (i.e. evaluate A and B). .