Question

Buckeye Nuclear Power is a nuclear plant that provides electricity for southern Ohio. There was an accident and iodine-131 was emitted into the atmosphere. The half-life of iodine-131 is 8 days. If a total of 200 g of iodine-131 was emitted, how much ¹³¹ I would remain after 3 months? Show all of your work and report your answer in % remaining.

2. Buckeye Nuclear Power is a nuclear plant that provides electricity for southern Ohio. There was an accident and iodine-131 was emitted into the atmosphere. The half-life of iodine-131 is 8 days. If a total of 200 g of iodine-131 was emitted, how much 131I would remain after 3 months? Show all of your work and report your in % remaining 3. Using the table below to answer the following Type of Emission Alpha Beta Gamma Beta Half life 4.4 x 109 years Element 238 234 Th 40 K 131 T 24.1 1.3 x 109 vyears a. Which radionuclide would you expect to have the lowest specific activity? Briefly explain your answer b. Which radionuclide would you expect to have the greatest specific activity? Briefly explain your answer c. Which radionuclide has the highest energy emission? Briefly explain your answer d. Which radionuclide has the lowest energy emission? Briefly explain your answer e. Gamma radiation can penetrate everything but lead, however alpha radiation cannot penetrate a sheet of paper. Do vou agree or disagree with the following statement? Gamma radiation is more dangerous to biological tissue than alpha radiation. Briefly explain your answer

Answer 1

For this first we need to find the Rate constant and the Rate constant is given by the formula given below.

K=0.6931/t_1/2

K=0.6931/8=0.08664

The formula shown below helps to find the product after decay.Here the t is number of days which equals 120days i.e 3months.

A=A₀e^-Kt

A=200 e^-0.08664*120

A=200*0.0000305

A=0.006106g.

Therefore, 0.006106grams of Iodine-131 remains after 3 months.