Homework Answers
state1:-(p=2 bar,t=47c)
n1=5(total no of moles)(kmole/s)
n1_co=n1*0.4(no of moles of co)=2
n1_n2=n1*0.6(no of moles of n2)=3
enthalpy values per mole (from tables)
h1_co=-109889(KJ/Kmol)
h1_n2=639.6(KJ/Kmol)
state2:-(p=2 bar,t=147c) //mixing takes under constant
pressure//
n2=x(let it be an unknown)
n2_co2=n2*0.55(no of moles of co2)
n2_n2=n2*0.45(no of moles of n2)
enthalpy values per mole(from tables)
h2_co2=-388643(KJ/Kmol)
h2_n2=3556(KJ/Kmol)
state3:-(p=2 bar,t=77) //mixing takes place under constant pressure//
enthalpy values per mole(from tables)
h3_co2=-391498(KJ/Kmol)
h3_n2=1512(KJ/Kmol)
h3_co=-109015(KJ/Kmol)
n3_n2=n1_n2+n2_n2
n3_co2=n2_co2
n3_co=n1_co
Applying energy equation for the SSSF process
W=0
Q=0
enthalpy inlet=enthalpy outlet
n2_co2*h3_co2+h3_co*n1_co+(n1_n2+n2_n2)*h3_n2=n1_n2*h1_n2+h1_co*n1_co+n2_co2*h2_co2+h2_n2*n2_n2
On solving for n2 (i.e, x) using above equation we get
n2_rate_flow(x)=1.753(kmole/s)
n3_total=(n1_co+n1_n2+n2_n2+n2_co2)=6.753
n3_co=n1_co=2
n3_co2=n2_co2=0.9642
n3_n2=n1_n2+n2_n2=3.789
Outlet molarfractions respectively
y3_co=n1_co/n3_total (molefraction of
co)=0.2962(no units)
y3_n2=(n1_n2+n2_n2)/n3_total (molefraction of
n2)=0.5611(no units)
y3_co2=n2_co2/n3_total (molefraction of
co2)=0.1428
M_co=molarmass(co)=28.01
M_co2=molarmass(co2)=44.01
M_n2=molarmass(n2)=28.01
M_mixture=y3_co2*M_co2+y3_n2*M_n2+y3_co*M_co=30.3(kg/kmole)
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