Question

thermal physics question

A muscle can be thought of as a fuel cell that produces work from the metabolism of glucose CeH1206 602-6C02 6H20 Relevant data on the reactants and products are tabulated below: H (kJ/mol) -1273 0 | Δ/G (kJ/mol) -910 0 -394.4 237.1 | Glucose O2 (g) CO2 (g393.5 H2O (1) S (J/Knol) 212 205 214 70 -285.8 5. Assuming ideal operation at room temperature, how much work could your muscles 6. Still assuming ideal operation, will heat be absorbed or expelled by the chemicals 7. Use the concept of entropy to explain why heat flows in the direction that it does perform in return for the metabolism of one mole of glucose? during the metabolism reaction? How much? during the metabolism of glucose

Answer 1

Answer:- Give that A musch ca-hoght d a a fuel Cell ucose The Chemi cal eache bhoeen glucobe &i ver above Cc tt 12.06 1-12 3 a lo 912 2- - 393.5 3a4 The. DH, DG are the ethalpy

And he gibbs enernartn fer anc mo the. mateial A ata atand lbar For cach meglucose cnu et us assume ideal o pevatiam 尸water) final piam the tabla

61O 6-1チ1 4.28J-(12お +236), DHfolchemica,.,tec.ct彻 The.ualueet. i5-2803·04 kg lmet The maximum ameuot TD kno he much eat i obsorbed ov expelied the chemia du

Duing -he metabelasm lslucoe heat enyabbel b he chea The heatabsovbed by the chemical IS プ by using the concept 염 entor To explan y the heat -flocos i he divechien the aeaclaot a The. en SC602) 230. 84

12.8420 The change in enepy =1チ043]k-1442丁k The eystmgaia 2G2 alaving entio Because he. entoy inclease heato)