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IM HAVING DIFFICULTIES TO IDENTIFY NMR, can you please explain in details this answer and whats the easiest way to read it
The reaction is worked up and compared to the starting material by NMR Staring material (methyl (S 2-methy-4-cxobutanoate) Pr


For example, if you had an alcohol and an aldehyde in the same molecule and selectively oxidize one and not the other, you wo
The reaction is worked up and compared to the starting material by NMR Staring material (methyl (S 2-methy-4-cxobutanoate) Product зн 러 зн H 24 3H 2H 10 PPM 2 PPM Question #14: Does it appear that the correct product has formed? Examine your reasoning type your text here
For example, if you had an alcohol and an aldehyde in the same molecule and selectively oxidize one and not the other, you would need a protecting group. Like in the synthesis shown below, to selectively oxidize the aldehyde, we make a semi- acetal out of the alcohol, making it enert to our oxidant. From there we can oxidize the aldehyde, followed by removing the protecting group Ho H Na2Cr20 O H2SO4, H20 Or Question #2: What would have happened in the second step if a protecting group was not used? H2O, H if not use the reagent would have oxidized from но он alcohol group to carboxylic acid, with oxidation of aldehyde. DOLL
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