Question
Number 7 (abstract algebra)

6. Consider the system of equations:yy , Consider the system of equations: +1 Are all the coordinates of all the points of in
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Answer #1

A constructible number can be formed by finite number of additions, subtractions, multiplications, divisions, and extraction of square roots of integers. In particular, integers are constructible.

7. If we solve the 2 given equations to find the points of intersection, we find that the only possibility is for x to be an integer. Hence y=x2 + x + 1 is also an integer for all x which are x coordinates of points of intersection of the 2 curves.

So, all the coordinates of all the points of intersection of these 2 curves are integers, and therefore constructible numbers.

To show this, we just solve the given system

xy - y = 7 \\ y = x^2 + x + 1

At any point of intersection, the y coordinates are same. So, we substitute the second expression for y in the first. This will give us a polynomial equation in terms of x alone, which can then solved.

r(x2 + x + 1) _ (x2 + x + 1) = 7

The only value of x satisfying the above is x = 2.

The corresponding value of y is  y=22 +2+1=1+2+1=7.

The only point of intersection of the given curves is (2, 7).

To conclude, all the coordinates of all the points of intersection of the given curves are constructible.

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