Question

MULTIPLE REGRESSION

*****PLEASE HELP ME WITH PART E
researcher emplo e turinde ender variables in a re ession mnde to reti a measure cf hie navel y eve a vaca n ns c osen by 4 8 9t e enden var ab es were画 = number roun«s ם gal per number c ge ers. r ear, x vaca IDns a en x number of yeare played golf, and xaverage golf score. Complete parta a through h. Dependent variable p-value .C01 F-value R2 4.4 Novelty level 4.63 ea table of crtical vaues af Click here to view a table of critical values of the F-distribution for alph8-0.05 Click here to 'new a table of cntical vaues of the F-distribution for alpha弌01. a. Give the hypothesized equation of a first-order model for y= novelty lawl. n view atabile of critical v af the F b. A test of Ho : Ps-0 warsus Hd,p,-0 yielded ล p-value of 0.008. Interpret this result if 0.01 Reject c. The estmate or was found to be negative. Based on this resul (and the result of part b), the researcher concluded that 'those who have played gelr for more years are less apt to seek novelty in their galr vacations." Do you agree with this statement? You should agrse bacause the researchers concusion matches d. The regression results, based on data colected for vacationers, are summarized in the table in the prob em statement. Give the null hypothesis for testing the overal adequacy ef the first-order regress on model. the null hypothesis becausre there ıs enauch ev dence ip support the alternative hytalhesis H"阝3 < the results of the test in part b Give the rejection repon for the test, part d. for α-0.025. F TRound to two decimal places as needed.)
AT THE BOTTOM*****

PLEASE HELP ME UNDERSTAND HOW SOLVE PROBLEM IF YOU KNOW HOW TO DO MULTIPLE REGRESSION

Answer 1

Solution:
Given:

N = Total sample size = 408

k = number of independent variables = 4

Level of significance = $\alpha =$ 0.025

Part e) Find rejection region

We have to find F critical value.

We use following excel command:

=F.DIST.RT( probability , df_numerator , df_denominator)

Here

df_numerator= k = 4

df_denominator = N - k - 1 = 408 - 4 - 1 = 403

Thus

=F.DIST.RT( 0.025 , 4 , 403 )

=2.82

Thus F critical value = 2.82

Thus rejection region is:

F > 2.82