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please explain how the pH was gotten.. especially the 10^-2.7 how do i put that in my calculator
Part A Imagine that you are in chemistry lab and need to make 1.00 L, of a solution with a pH of 2.70 Assuming the final solu


Part A Assuming the final solution will be diluted to 1.00 L, how much more HCI should you add to achieve the desired pH? Exp
Bases and t Mixing Strong Acids l Review 1 Constants | Periodic Table Imagine that you are in chemistry lab and need to make
Part A Imagine that you are in chemistry lab and need to make 1.00 L, of a solution with a pH of 2.70 Assuming the final solution will be diluted to 1.00L how much more HCl should you add to achieve the desired pH? Express your answer to three significant figures and include the appropriate units. You have in frort of you View Available Hint(s) . 100 mL of 7.00*102 MHCL , 100 ml of 5 00×10-2 M NaOIL and plenty of distiled water You start to add HCl to a beaker of water when someone asks you a question. When you return to your dilution, you y grab the wrong cylinder and add some NaOH alue Units Once you realize your error, you assess the situation. You have 85.0 mL of HCI and 90.0 mL of NaOH eft in their original containers.
Part A Assuming the final solution will be diluted to 1.00 L, how much more HCI should you add to achieve the desired pH? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) mL 19.7 Submit X Incorrect; Try Again; 5 attempts remaining Provide Feedback
Bases and t Mixing Strong Acids l Review 1 Constants | Periodic Table Imagine that you are in chemistry lab and need to make 1.00 L of a solution with a pH of 2.70. You have in front of you . 100 mL of 7.00×10-2 MHCL . 100 mL of 5.00×10-2 M NaOH, and , plenty of distilled water. You start to add HCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some NaOH Once you realize your error, you assess the situation. You have 85.0 mL of HCl and 90.0 mL of NaOH left in their original containers.
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Please explain how the pH was gotten.. especially the 10^-2.7 how do i put that in my calculator
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