Question

Cz 개2 Ci R1 Take RL = 20 kn, R1 = R2 10 An active network is representedas shown above. (a) Use Multisim or PSpice to determine the frequency response of the network. (b) Obtain the equivalent passive network, i.e. an RLC circuit that will have the same frequency response. e2t u(t), find the output signal vo (t) of the (c) Given the input signal vs (t) passive network in (b). (d) Given the output signal vo (t) 4 sin (2T108 t), find the input signal vs (t) of the passive network in (b). Submit your solution/report in hard copy to your professor AFTER it is graded, submit the graded report electronically to Taskstream.

Answer 1

Its High pass filter and on analysis in PSpice, its observed that, cut off frequency of the circuit is 5Hz

oKOL SLF oke okUL AVac Vout eguemau yes ponse Can be chele Prom that obtaimeal from p-spice hat aiven Lmijar equeu response can be obtaim assive ser circit as qivem below usim 2 RTRC cat 6-3k Thun R Vout

Both circuit simulated in PSpice and obtained same result with cut off frequency 5Hz.

Diagram of Op-Amp Active filter simulated in PSpice

0V 0V O PAMP R1 C1 OPAMP OU 0V 20k C2 OU U2 R3 10 U1 0A 4Vac 0Vdc R2 10k 0A 0A 0V

Result of Simulation of above active filter

3. DU 2.QU 12H2 16H2 24Hz 28H2 32Hz 36Hz 40H2

Diagram of Passive filter simulated in PSpice

C2 OV 0V 5u 0A R2 6.3k 5 0Vdc oV 0

Result of Simulation of above passive filter

.OU 2.ลบ 12Hz 16Hz 32Hz iHz 2 Hz 24Hz 28Hz 36Hz a U(R2:2)