a) in a complementation test mutants which shows the same phenotype is crossed, this is to identify the number of genes involved to produce normal phenotype and the number of alleles of each gene.
b) if 2 mutants are can complement the phenotype that is the in the hybrid shows wildtype phenotype then the 2 mutations are in 2 different genes if 2 mutants cannot complement the phenotype means, 2 mutations are in the same gene, so the hybrid lacks one gene in the pathway.
so here
1,7-A
2,12-B
3,6-C
4,8,11-D
5,10-E
9-F
are different complementation groups, so there are 6 genes involved in the pathway, A, B, C, D, E, F.
and 1,7 are alleles of A
2,12 are alleles of B
3,6 are alleles of C
4,8,11 are alleles of D
5,10 are alleles of E
9 is the only allele of gene F
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