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the Consider reaction A203(s) +2Fe(s) Fe2O3(s) +2AIs) for which ΔH° = 851.5 kJ and Δ So-37.00 J/K at 298.15 K (1) Calculate t
needed for this question. Consider the reaction 2H2S(2) +302g 2H20) +2S02(g) for which AFP-一1.124 x103 kJ and Δ So- 390.7 J/K
the Consider reaction A203(s) +2Fe(s) Fe2O3(s) +2AIs) for which ΔH° = 851.5 kJ and Δ So-37.00 J/K at 298.15 K (1) Calculate the entropy change of the UNIVERSE when 2.154 moles of Al203(s) react under standard conditions at 298.15 K JK (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose reactant favored. enthalpy entropy both reactant favored SNext SubilA
needed for this question. Consider the reaction 2H2S(2) +302g 2H20) +2S02(g) for which AFP-一1.124 x103 kJ and Δ So- 390.7 J/K at 298.15 K (1) Calculate the entropy change of the UNIVERSE when 2.347 moles of H2S(g) react under standard conditions at 298.15 K J/K universe (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose reactant favored'. enthalpy entropy both reactant favoreds Submit r Retry Entire Group
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Answer #1

E-Consider the reaction : for which AH- 851.5 kT and AS 3.ODJl at 298.15k i. Calculate the entr pod change-牛the cober) อ.154eous Since AG is positive the veaction is nons A Guniverse is negative this adso imdicales the reaction is no-spmtapeous ksheASuniverse t-8.389-kJk. - ーsubstitute-the-values-44 AHJ-AS 389K As universe- AC 2 1-3 -298-15k asunivei se 、 8-389sk Since △9

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