The value of ΔG°\' for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is 7.53 kJ/mol. If the concentration of dihydroxyacetone phosphate at equilibrium is 2.85 mM, what is the concentration of glyceraldehyde-3-phosphate? Assume a temperature of 25.0 °C. The constant R = 8.3145 J/(mol·K)
Dear student
Use the following equation and solve for K:
e^∆G/-RT=K
Where
∆G=7.53kJ/mol=7.53 x 10^3 J/mol
R=8.3145 J/(mol·K)
T=273K + Cº=273K+25=298K
e^[7.53 x 10^3 J/mol/-8.3145 J/(mol·K)*298K]=K
K=4.788 x 10^-2
The reaction is as followed:
dihydroxyacetone phosphate ------------------->
glyceraldehyde-3-phosphate
K=products/reactants
K=[glyceraldehyde-3-phosphate]/[dihydroxyacetone phosphate]
K=x/2.35mM
K=4.788 x 10^-2=x/2.35mM
Solve for x:
(4.788 x 10^-2)*(2.35mM)=x
x=0.112mM
glyceraldehyde-3-phosphate=0.112mM at equilibrium
Regards
Team Keep Learning
Please do upvote if you like my answer
The value of ΔG°\' for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate...
The value of ΔG°\' for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is 7.53 kJ/mol. If the concentration of dihydroxyacetone phosphate at equilibrium is 2.65 mM, what is the concentration of glyceraldehyde-3-phosphate? Assume a temperature of 25.0 °C. The constant R = 8.3145 J/(mol·K) [GAP] = ??? mM
CH6Q17 The value of ΔG°'ΔG°′ for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is +7.53 kJ/mol+7.53 kJ/mol. If the concentration of dihydroxyacetone phosphate at equilibrium is 2.25 mM2.25 mM, what is the concentration of glyceraldehyde-3-phosphate? Assume a temperature of 25.0°C25.0°C. [GAP]= _________ mM
The value of Δ G ° ' for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is + 7.53 kJ/mol . If the concentration of dihydroxyacetone phosphate at equilibrium is 2.45 mM , what is the concentration of glyceraldehyde-3-phosphate? Assume a temperature of 25.0 ° C . [GAP] = mM
For the aqueous reaction dihydroxyacetone phosphate is the reactant and glyceraldehyde 3 phosphate is the product. dihydroxyacetone phosphate↽−−⇀glyceraldehyde−3−phosphate dihydroxyacetone phosphate ↽ − − ⇀ glyceraldehyde − 3 − phosphate the standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol Δ G ° ′ = 7.53 kJ/mol . Calculate Δ? Δ G for this reaction at 298 K 298 K when [dihydroxyacetone phosphate]=0.100 M [dihydroxyacetone phosphate] = 0.100 M and [glyceraldehyde-3-phosphate]=0.00400 M [glyceraldehyde-3-phosphate] = 0.00400 M .
For the aqueous reaction н CH2ОH H OH СHа-0- CH2-0- dihydroxyacetone phosphate glyceraldehyde-3-phosphate the standard change in Gibbs free energy is AG = 7.53 kJ/mol. Calculate AG for this reaction at 298 K when [dihydroxyacetone phosphate] 0.100 M and [glyceraldehyde-3-phosphate] 0.00400 M 108 kJ/mol AG =
For the aqueous reaction dihydroxyacetone phosphate is the reactant and glyceraldehyde 3 phosphate is the product. dihydroxyacetone phosphate − ⇀ ↽ − glyceraldehyde − 3 − phosphate the standard change in Gibbs free energy is Δ G ° ' = 7.53 kJ/mol . Calculate Δ G for this reaction at 298 K when [dihydroxyacetone phosphate] = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00300 M .
In another key reaction in glycolysis, dihydroxyacetone phosphate (DHAP) is isomerized into glyceraldehyde-3-phosphate (GAP): The equilibrium constant is 5.4×10−2. Calculate the equilibrium fraction of GAP from the above, at 37 ∘C. CH2OH HC-OH ΔGor = +7.5 kJ/mol CH2OPO22 CH2OPO2 GAP DHAP
help with 15 and 16 Dihydroxyacetone (DHA) isomerizes to glyceraldehyde 3-phosphate (G3P): K = 0.0475 G3P (aq) DHAP (aq) what is the standard free energy change (AG") for this reaction and is this reaction exergonic or endergonic? R = 8.3 14 J mol-1 K-1 and T = 298K +7.55 kJ mol-1 II. 3.28 kJ mol1 III. -7.55 kJ mol- +3.28 kJ mol so the reaction is Vexergonic VI. endergonic CAlI and V HtI and VI A I and V b....
For the aqueous reaction the standard change in Gibbs free energy is Delta G degree = 7.53 kJ/mol. Calculate Delta G for this reaction at 298 K when [dihydroxyacetone phosphate] = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00400 M. The constant R = 8.3145 J/(K middot mol) Delta G =
emates 3 Homework Bioenergetics Biochemical reactions Resources Hint The value of AG® for the conversion of glucose-6-phosphate to fructose-6-phosphate (F6P) is +1.67 kJ/mol. If the concentration of glucose-6-phosphate at equilibrium is 2.55 mm, what is the concentration of fructose-6-phosphate? Assume a temperature of 25.0°C. [F6P] = mM