Two loudspeakers, 5.0 m apart and facing each other, play identical sounds of the same frequency....
Two loudspeakers, 5.0 m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them, where there is a maximum of sound intensity. Moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved 0.35 m . Assume the speed of sound is 340 m/s.
Part A: What is the frequency of the sound?
Express your answer with the appropriate units.
Part B: If the frequency is then increased while you remain 0.35 m from the center, what is the first frequency for which that location will be a maximum of sound intensity?
Express your answer with the appropriate units.
Homework Answers
L1 = (L/2) + 0.35 = 2.5 + 0.35 = 2.85 m
L2 = 2.5 - 0.35 = 2.15 m
Path difference, phi = 2.85 - 2.15 = 0.70 m
Lambda = 2 x 0.7 = 1.4 m
Frequency, f = 340/1.4 = 242.85 hz
B)
Frequency, f = 340/0.7 = 485.71 hz
Comment in case any doubt please rate my answer ...
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