Question

Modeling of RLC circuit This model is about the RLC circuit. In this circuit, resistance IR, inductor IL), and capac tor ICI

or, 2 4001D00 or,20 500,00ca 0 using characte istic equation, we get + 200(+ 500,000 = D r--100 700 Therrfare, the gerieral

can you please add a battery or AC source and then find the solutions and compare with the results from the Pic RLC circuit solution.? A quick, clear response will be rated. thank you,

Modeling of RLC circuit This model is about the RLC circuit. In this circuit, resistance IR, inductor IL), and capac tor ICI are connected in series. We will derive the fonmula for the total charge ()following through the circuit using secon rr diferental equatc. Here, wrwb usingsbasi physis corirpts, farnulas of currentvtagrhargral and their derivative, integral with resprct to re arther in to obtain the total chare following through the circuit and study its behavior Fig: RLC series cirruit The voltage acros the indurtor is giv ty,VLIddt) Sirnilarhy, the rurrent follouw ng through caparitor isgir ty l- C(dvttVl1/C) Idt Acrordirigt kirhoffs vltage law, thr sur of all the valtagrs in a rlosed loop is ze. i.r V Sirnilarly, the rurrent is adrfined s trof lw of crlI, (dQdt Q Therefore, substituting thrsal in ru1), wr grt This is the eneral equation of RLC series circuit. Suppose, we are given an RLC series circuit where 1 coulomb charge is flowing a current of 3A through the circuit at t-o and values for resistance, inductor and ca oacitor are 40Q, 0.2 H and 10.H respectively, Hrre, 010 10,1-n 3A, R-40 a, L-0.2H, an C 10 H Plugging these values in equation (2] or, 2" 4001D00 or, Q200 5Co,0000 0 using characteristic equation, we get r+ 200r 500,000 0 r--100 700 Therrfare, the gerirral equaticorı for the rquatin hang riplxugate raats is give by r, Q-(C,cos700! + C.sin700t)) Taking drrivtiveof Q with rrspirct to t
or, 2" 4001D00 or,20 500,00ca 0 using characte istic equation, we get + 200(+ 500,000 = D r--100 700 Therrfare, the gerieral equatican for the rquatin hang riplxougate raats is give by r, Q- (C,cos700t! + C.sin(700t) Taking derivtivr ofQ with rrspt to t Q' : 100 ri叫Ccoslarp,+c.sinporrl)-ea卟7 OCsin(700リー700c,cosi7nm).-14 Applyingconditinns Ql) d uatis arid 4 0(01-1→C=1 or, 3- -100700103/700) Therefore, aspagos(700t)+1103/7001e4. sin;700tl
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ao fL О.LH 1000 O fivsamd So OoOo Soo0Oo So -(cot ^ -1004 ThnUm o t 700

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can you please add a battery or AC source and then find the solutions and compare with the results from the Pic RLC circuit solution.? A quick, clear response will be rated. thank you, Modeling...
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