Computer Architecture
Please help me explain the answer
LDR r5,[r4, #12] means B[3] since one address correspond to 4 byte therefore 4*3 = 12
ADD r3,r3,r5,LSL #2; this means r3=r3+ r5<<2 shift and rotate by 2 results 3rd index
LDR r5, [r3,#0] -> r5 <- r3+0 // A[B[3]]
ADD r0,r1,r5 // f = g + A[B[3]], f = r0
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Computer Architecture Please help me explain the answer 3 For the following statement, translate the statement to ARM assembly code. Assume that variable fand g are each in register rO, r1. Base addr...
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