Question

3. From a laboratory test given the following parameters calculate hydraulic conductivity Area of cylinder 0.33 ft, A; Area of inlet tube 0.0417 ft a; ho 3 ft; the water level in the inlet tube drops 2 ft in 15 minutes, the length of the core is 1.5 ft-L 0 hours

Answer 1

The velocity v of the inlet tube is (2ft)/(15minute) = 0.13 ft/min

v = K*i

where K is the hydraulic conductivity and i is the hydraulic gradient

i = h_o/L

where h_o is the hydraulic head and L is the length of specimen (or core)

Here h_o = 3 ft , L = 1.5 ft (given)

So, i = 3/1.5 = 2

then, as v = K*i

So, K = v/i = 0.13/2 = 0.065 ft/min = 93.6 ft/day

So, the hydraulic conductivity is  93.6 ft/day.