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Name December 9th, 2018 Student # final test Prof. Ivan J. Baiges INGE 3032 Applied Mechanics - Dynamics PROBLEM 2 A 500 lbf

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Answer #1

This is a collision problem

a)

velocity of elf

v_1= -3.5ft/s

Velocity of venado at the bottom

v = \sqrt(2gh)

u = v/(2 * 32.2 * 20) 35.9ft/s

This can be resolved into:

- 35.9cos20i - 35.9sin20j

33.73i _ 12.28 u

33.73 t1ro

Velocity after an inelastic collision is given by:

ejm2 VI + mi + m2 mi + m2

m2em1 1m1+m2 01 mi + m2

substituting e = 0.65 and masses and velocities, we get:

U2= 21.84ft/s

1,1-46.04ft/s

b)

Impulse is distruction of momentum

I =( m_1v_1+m_2v_2) - (m_1v_1'+m_2v_2')

1 (500 * (33.73-21.84) + 120 * (-3.5-46.04))/32.2 0.0062

c)

average impact force:

F = 1/(0.2sec)

F0.0310

d)

If it slides 20ft after collision,

Its energy is absorbed by friction in that distance.

f*20ft = KE

f*20ft = (1/2)(120/32.2)*v^2

f*20ft = (1/2)(120/32.2)*46.04^2

f = 196.486 lbf

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Name December 9th, 2018 Student # final test Prof. Ivan J. Baiges INGE 3032 Applied Mechanics - Dynamics PROBLEM 2 A 500 lbf reindeer (venado) goes down a 20° slope (with NO FRICTION ON THE SLOPE) fr...
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