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Please answer part A,B,and C. Also, please explain your steps as you work through the problem. thanks.
(A) Caculat te reccion Corux AN 25hw.
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Answer #1

3 kN/m 3. YM eam ABC 15kN 3 KN/m 6 2.2S m Cy(+) + 25 =15x2 Beam ASC .. 3(4-5+1-5) +1.25 Ayt By = By- 13-667 kN () Ay 5.583 kNca* at Point E Intei NE 2-25 m Ay5 S83 kN 2-2S ME= S-583 (2.25 ME = 4.368 kN-m 5 kN Intennal foarcA at PontF F C 2m , Dyー13.T

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Please answer part A,B,and C. Also, please explain your steps as you work through the problem. thanks. (A) Caculat te reccion Corux AN 25hw. (A) Caculat te reccion Corux AN 25hw.
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