Question

QUESTION 12 (12-14) For the below figure and knowing that F21 -0.15, F31 0.0085, Wa5m, e10.2,82 :0.6 ε3:0.9 find the following: T3 300 K 4 m in T, = 400 K 3 m T,=500 K 41 2 m What is F13 0.034 0.0085 0.154 0.068 0.017 QUESTION 13 The net amount of heat transfer from surface 2 to surface 1 O -4.22 w O-1.91 w 23.3 w 2.35 w QUESTION 14 The net amount of heat transfer from surface 1 to surface 3 351.6 w 20.34 w 921.6 w 884.7 267.2 w

Answer 1

300K A, - 20 Given 3 Surfaces aranged as Slaou 2 0.15, 3/ 400k 2 to 5oou two f。Viem. So we caill succeed as and A, a receivi 3S ailro hen se Conde A and A, (35)(0.07): 10(5,4 Surface 2 and and p ging alro Considevin? 13 2 0.242-0.225 2 0.0#7 . 2)To find Heat kanfer hovm Suface 2to su、face , 2- 21 - 2.35 ww bid answers (Ophang) provided aveau ;n w w ise dousts

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