Question

1. You are visiting the Adventure AquariumTM in Camden, NJTM enjoying some time relaxing and looking at fish. One fish is floating near a fixed piece of reef material at the same level as vour eves and stays there for a long time. You decide to call him George. As you and George sit calmly observing each other, you wonder how far away George really is from you compared to his/her actual distance from you You also wonder what George sees and how far away you appear to be from George. Your face is about 8cm from the glass. After asking an attendant at the aquarium, you learn that the glass is 3cm thick and has an index of refraction of 1.8. Use 1.33 as the index of refraction of the water. In addition, the piece of reef that George is floating near is 6.8cm from the glass You decide to compute the apparent distance between your face and George's image as well as the apparent distance from George to your image

One may assume the rays relevant for image formation are making small angles relative to the normals of the glass.

The position of the coral is meant to be the actual physical position of the fish.

My professor told us we’d have to use Snell’s Law in an unusual way when solving this problem.

Answer 1

P. fisn (Grcora) g cm Crn from Snell's lauw 2. I Sin ei for small anglas Sin entane herefo taner tan et appasent dista of tenta from you

1 Fish as n by youl 233 9 cn CF CF 9 BF ghw shit 0-3 m A 2cm wene Pih o seen by you is at α des tance

2. You os Seern by fish Ale 133 AB = 6.01 cm ラ·AC 32 T.32 OuHuol distance oo You as Sn by the fish apfear to be 14.16 cn