please explain steps to solution using excel.
3) Let
now we use the Newton's formula to find root
We use the following formulae in the excel sheet to do this task
the first cell B3 has a starting value -2
we then insert the following formula for the remaining cells of the first column , which is the Newtons formula
=B3-(C3/D3)
to find f(x) we insert the following formula,
=EXP((B4^2)*SIN(2*B4))-4
to find f'(x) we insert the following formula,
=EXP((B5^2)*SIN(2*B5))*((B5^2)*COS(2*B5)+SIN(2*B5)*(2*B5))
the following table is obtained
X | f(X) | f'(X) |
-2 | 16.63957 | -116.4439907 |
-1.85710 | 2.479718 | -31.82297492 |
-1.77918 | -0.39829 | -15.61331576 |
-1.80469 | 0.343053 | -19.69367324 |
-1.78727 | -0.18027 | -16.80410716 |
-1.79800 | 0.132826 | -18.52796253 |
-1.79083 | -0.07954 | -17.35703206 |
-1.79541 | 0.054718 | -18.09648888 |
-1.79239 | -0.03445 | -17.60505401 |
-1.79435 | 0.022997 | -17.92152913 |
-1.79306 | -0.01478 | -17.71335332 |
-1.79390 | 0.00974 | -17.84844907 |
-1.79335 | -0.00631 | -17.75998974 |
-1.79371 | 0.004138 | -17.8175776 |
-1.79347 | -0.00269 | -17.77994458 |
-1.79363 | 0.00176 | -17.80447665 |
-1.79353 | -0.00115 | -17.78845891 |
-1.79359 | 0.000749 | -17.79890638 |
-1.79355 | -0.00049 | -17.7920874 |
-1.79358 | 0.000319 | -17.7965361 |
-1.79356 | -0.00021 | -17.79363292 |
-1.79357 | 0.000136 | -17.79552715 |
-1.79356 | -8.9E-05 | -17.79429107 |
-1.79357 | 5.78E-05 | -17.7950976 |
-1.79356 | -3.8E-05 | -17.79457132 |
-1.79357 | 2.46E-05 | -17.79491472 |
-1.79357 | -1.6E-05 | -17.79469064 |
-1.79357 | 1.05E-05 | -17.79483686 |
Fro the table, the root is x = -1.79357
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