A multinomial experiment with k- 4 cells and associated cell counts produced the data shown in the following table. Category 1 Category 2 Category 3 Category 4 62 |42 |37 Test the following hypothes...
3. A multinomial experiment with k-4 cells and n=201 produced the data shown in the one-way table to the right. Complete parts a through e. CELL 1 CELL 2 CELL 3 CELL 4 60 Do these data provide sufficient evidence to conclude that the multinomial probabilities differ? Test using alpha=0.10. What is the null and alternative hypothesis? II. Calculate the test statistic. (6) III. Calculate the p-value. IV. What is your conclusion?
2. Multinomial Data: A multinomial experiment with k=3 cells and n-320 produced the data shown in the accompanying table. Do these data provide sufficient evidence to contradict the null hypothesis that p1 0.25, p2-0.25 and p3-0.5? Assume a Type I error rate of 0.05. Cell ni 78 60 182
2. Multinomial Data: A multinomial experiment with k=3 cells and n-320 produced the data shown in the accompanying table. Do these data provide sufficient evidence to contradict the null hypothesis that...
CH12 Q2
Consider a multinomial experiment with n 280 and k 3. The null hypothesis is но. p1-0.40, p2-0.40, and p3-0.20. The observed frequencies resulting from the experiment are: (You may find it useful to reference the appropriate table: chi-square table or F table) Category Frequency 120 110 50 a. Choose the appropriate alternative hypothesis. All population proportions differ from their hypothesized values. At least one of the population proportions differs from its hypothesized value. b-1. Calculate the value of...
Consider a multinomial experiment with n = 260 and k = 4. The null hypothesis to be tested is H0: p1 = p2 = p3 = p4 = 0.25. The observed frequencies resulting from the experiment are: (You may find it useful to reference the appropriate table: chi-square table or F table) Category 1 2 3 4 Frequency 73 44 75 68 a. Choose the appropriate alternative hypothesis. All population proportions differ from 0.25. Not all population proportions are equal...
A multinomial experiment produced the following results:
(You may find it useful to reference the appropriate table:
chi-square table or F table)
Category
1
2
3
Frequency
117
100
83
a. Choose the appropriate alternative
hypothesis at H0: p1 =
0.50, p2 = 0.30, and p3 =
0.20.
All population proportions differ from their hypothesized
values.
At least one of the population proportions differs from its
hypothesized value.
b. Calculate the value of the test statistic.
(Round intermediate calculations to...
1A)
1B)
1C)
1D)
You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: H:PA = 0.1; P = 0.3; Pc = 0.1; Pp = 0.5 Complete the table. Report all answers accurate to three decimal places. Observed Expected Category Frequency Frequency А 17 B 43 с 12 D 48 What is the chi-square test-statistic for this data? x = What is the P-value? P-Value = For significance...
Category Observed Counts A gene called ACTN3 encodes a protein that functions in fast- twitch muscles. People have different variants of this gene, classified as RR, RX, or XX. RR 130 Using the sample data provided in the table, you want to test if the proportions in these categories are 0.4 (for RR), 0.4 (for RX), and 0.2 (for XX). RX XX 126 80 1. State the null and alternative hypotheses for this chi-square goodness-of-fit test. Ho: Ha: 2. What...
3. Let Yi ~ Binonial(nj:pj), J = 1, 2 independently. For testing the null hypothesis Ho : P1 = P2, a coinmonly used test statistic (slightly different frorn the one given in lecture) s Pi-P2 where pi = Y5/nj and p = (Yİ + Y)/(m + n2) is the pooled estimate of proportion urder Ho. Such data can also be surnmarized as a 2 × 2 table of counts Population Successes Failures Yi 2 For this table, denote the test...
1.Referring to the the Goodness-of-fit data shown in table 1. The calculated Chi-sq test statistic is A. 8.0 B. 12 C. 7.85 D.8.75 Table 1 Chi-Squared goodness-of-fit test H0: Follows Uniform Distribution H1: Does not follow Uniform Distribution Category Observed Expected Contribution To Chi-Sq 1 12 8 2.000 2 7 8 0.125 3 2 8 4.500 4 7 8 0.125 5 12 8 2.000 6 8 8 0.000
1. Use the data in the contingency table to answer the question. Columns Rows 1 2 3 Total 1 36 35 92 163 2 67 57 113 237 Total 103 92 205 400 You wish to test the null hypothesis of "independence"—that the probability that a response falls in any one row is independent of the column it falls in—and you plan to use a chi-square test. You are given that there are 2 degrees of freedom associated with the...