SIMULATION EXERCISE # 3 Mesh Analysis" Given the following network: R1 V2 2k 5V V1 k R4 Vs volls 12 Tk 3k R3 R5 1. Simulate the above network using Pspice, Choose a value of Vs for the left...
V1 Vo1 AD8eS V2 V02 D825 R1-0.5k, R2-2k, R3 0.4k, R4 1k, R5 5k, V1 10v, V2 5v Calculate V01-?, VO2-? and show how to calculate. All voltages is in reference to ground. Assume that both operation amplifier is ideal, and supply voltages is +20v.
(34pts) 2. Using superposition, find vs. Given: R1=102, R2=2292, R3=3052, R4=4412, R5=5082, V1=20V, V2=24V and I=4A. RIR R5 NNN www R2 01 vi R4 v2
electrical circuit 2). Using Mesh analysis, Calculate the current through resistor R5. R2=2022 R1=102 R3=30 12 R4=4022 V1=60V R6=6022 R5=502 15A R7=702 R8=80 V2-40V R9=902 R10=1002
2). Using Mesh analysis, Calculate the current through resistor R5. R2=2022 R1=102 R3=302 R4=402 V1=60V R6=6022 R5=502 15A R7=702 R8=802 { V240V R9=902 R10=1002
calculate voltage v1,v2,v3 and VS r1=1k r2=2k r3=3.9k r4=5.6k Tabla 3-1 Resultados de Divisor de Voltaje Ri - R3 RSUM Valor 0.98k r snike 3.82k ? Medido Voltajes V1 V2 V3 VSUM Calculados Voltajes V2 VSUM Medidos I 1.130 6.57V 4.39V I 12.000 VI V3 m Vn Iv> | 12 | Ts / Id Ous SR2 3 R3 RA I 2 = Un R2 Is=Izt IstJA Vs. Un On A Un ton R1 R ik un (12V) 1926 - RIAL...
RESISTOR VALUES: R1=1k, R2=2k, R3=3k, R4=3.9k, R5=5.1k, R6=6.2k, R7=6.8K NUMBERS: 2, 4, & 5 1 Short AB, as shown in Figure 3 - 2 (a). Use mesh analysis to calculate the voltage across each resistor and the current through AB, IAB 2. Leave AB open, as shown in Figure 3 - 2 (b). Use nodal analysis to calculate the voltage across each resistor as well as the voltage across AB, VAB 3. Find Thevenin's and Norton's Equivalent using the results...
using MatLab R611 + R1(11 – 12) + R2(11 – 13) = V1 R312 + R4(12 – 13) + Ri(12 – I1) = V2 R513 + R4(13 – 12) + R2(13 – 11) = V3. = = 2012, R3 512, R4 = 1512, R5 = Let the resistances be given by Ri 1012, R2 want to calculate the currents 11, 12, and 13. 3012 and R6 2512. We = (a) Write the equations in matrix form Ax b, where x...