Question

I HAVE the answer (B) but i dont know how to get it, please explain. my professor wrote down a bunch of equations but i dont understand them, please explain in words as if i were stupid.

i have attached the sheet of notes he wrote on this problem to make your life much easier, you dont really have to solve anything, as the answers are right here, all you have to do is literally explain to me how these equations work in real life and write it out in a way a dumdum would understand, Thanks! :) shouldnt be too hard for you so all i ask is just explain it so i understand it!

29. In the figure shown three boxes are connected by cords, one of which wraps over a pulley having negligible friction on its axle and negligible mass. The masses are mA = 32 kg, mB = 44 kg, and mC = 14 kg. After the assembly is released from rest, what is the tension in the cord connecting B and C?

A. 31.6 N

B. 48.8 N

C. 72.8 N

D. 137 N

E. 431 N

Thanks!

29. In the figure shown three boxes are connected by cords, one of which wraps over a pulley having negligible friction on its axle and negligible mass. The masses are mA 32 kg, mB 44 kg, and mc - 14 kg. After the assembly is released from rest, what is the tension in the cord connecting B and C? A. 31.6 N B. 48.8 N C. 72.8 N D. 137 N E. 431 N Free body diagram of each objects are: Newton's 2nd law: Find acceleration a, and then substitute the acceleration, a into the third equation to get T Adding three equation together, From the third equation, 32 32 44 14 32 90 - 14 9.8 = 48.78N

Answer 1

on blolK B 43.2+7-T,ー:@ 44 a : T. ↓a (4)19 3) -7 14a 1302-T 144(3) ses Tension between B and c 48.8 N