Please find below the network diagram. Critical path = ACEF.
Task | Preceding Tasks | Optimistic (a) | Most likely (M) | Pessimistic (b) | PERT Estimate = (a+4*M+b)/6 | Deviation = (b-a) / 6 | Variance = Square of (b-a) / 6 |
A | C,D | 44 | 50 | 56 | 50.00 | 2.00 | 4.000 |
B | D | 45 | 60 | 75 | 60.00 | 5.00 | 25.000 |
C | E | 42 | 45 | 48 | 45.00 | 1.00 | 1.000 |
D | F | 31 | 40 | 49 | 40.00 | 3.00 | 9.000 |
E | F | 27 | 36 | 39 | 35.00 | 2.00 | 4.000 |
F | End | 58 | 70 | 82 | 70.00 | 4.00 | 16.000 |
Critical path = ACEF Expected time | 50+45+35+70 | 200.00 |
Sum of variances on the critical path | 4+1+4+16 | 25.000 |
Z-score = (Specified time - Expected time)/ sqrt (sum of variance) | (160-200)/sqrt(25) | -8.0 |
For Z-score beyond -3.5, the probability is almost negligible i.e. there is no chance that project will be completed within 160 days.
3. A project starting this summer has following work breakdown structure Time Estimates (days) Activity Precs Optstic Most Likely Pes Start Pessimistic A, B C, D 56 45 42 31 27 End58 60 39 70 What is...
Please use the table to answer questions, SHOW WORK
Consider the following work breakdown structure for questions 46-50: Duration (Days) Most Start Finish Activity Node Node Optimistic Likely Pessimistic 50 31 70 41 35 59 34 82 41 58 32 30 5 46 What is the estimated expected (mean) time tor activity D? A 32 days B. 41 days C 44 days D. 42 days E 40 dayts 46 What is the estimated standard deviation for the critical path? A...