34)
use:
pH = -log [H+]
6 = -log [H+]
[H+] = 1*10^-6 M
use:
[OH-] = Kw/[H+]
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
[OH-] = (1.0*10^-14)/[H+]
[OH-] = (1.0*10^-14)/(1*10^-6)
[OH-] = 1*10^-8 M
pH here is Strong electrolyte
It will dissociate completely to give [OH-] = 1.0*10^-8 M
At equilibrium:
Cr(OH)3 <----> Cr3+ + 3 OH-
s 1*10^-8
Ksp = [Cr3+][OH-]^3
1.6*10^-30=(s)*(1*10^-8)^3
1.6*10^-30= (s) * 10^-24
s = 1.6*10^-6 M
Answer: D
Only 1 question at a time please
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