Question

Question 1 (30 Marks) Plate A is fillet-welded to Plate B as shown in Figure 1. Plate A and Plate B have the same material properties Both plates are 10 mm thick. There are two holes (with a diameter of d) in Plate A. It is assumed that weld failure will not occur (a) If Plate A has a yield stress (fy) of 350 MPa and an ultimate tensile strength (fu) of 450 MPa, what is the maximum load (P) Plate A can carry? The diameter of the holes is 22 mm. [15 marks] (b) If the material property of Plate A is changed to fy = 250 MPa and fu = 410 MPa, what is the minimum hole diameter (d) beyond which the fracture failure will govern? What is the corresponding maximum load (P) Plate A can carry? [15 marks] Plate B Fillet welds 100 mm 240mm Plate A Figure Relevant formulas are given below Nominal section capacity of a tension member (N) shall be taken as the lesser of N- Ag fy and Nt- 0.85 kt An fu In which, A,-gross area of the cross-section, An net area of the cross-section kt correction factor to allow for eccentricity of connections Capacity factor ф-0.9 1.0 for this question

Answer 1

Pate B PlatcA Since t is ossumes tnet weld ill not occuwe, And widtn of plate B is mone-than pide A so. plate Auǐ1/ a) we will chedss anen yielain- based on anea yi deduction diet, 2 hole. 1960mm a net ea csackin- may SSOS

b No ma*e pytat/ has chan uetuxe st Nt,ー 0.gs ktAn4, 2d冫200-172, 146 33.9 nm 33.9