The Code Word [C] = [m] * [G]
here G is Generator Matrix and m is the message
Now breaking m in to peices ,we have
m = [2 3 9 6] and the encoded message C1 is [2 3 9 6 33 137]
m = [1 4 3 8] and encoded message C2 is [1 4 3 8 39 100]
coding theory 1. If 100 031 Go 01 0 0 9 0001 27 01 0 054 is a generator matrix for a linear code over Fi encode the message stream m(2, 3,9, 6, 1,4,3, 8) (by breaking it into encodable pieces). 2....
Consider the 2-error correcting RS code over GF(8). Let α be a primitive element of GF(8). (a) List the parameters of the code. Find the generator polynomial of the code. Encode the message [1 α α2 ] systematically. (b) List the parameters of the binary expanded code. Provide binary equivalents of the encoding above. (c) Decode the received word [0 1 α α2 α3 1 0].